All categories

2 years ago

MATH WORK PLEASE HELP GIVING MANY POINTS ONLY DO THE ONES IN PURPLE!!

Mathematics

1 answer:

N76 [4]2 years ago

7 0

Answer:

Step-by-step explanation:

8,3,4,6,7,2,5,

You might be interested in

Marshall baked two kinds of cakes. Each cake was the same size. He served 1 half of the marble cake. He served 1 third of the le

Assoli18 [71]

Answer:

He served 3/6 of the lemon cake and 2/6 of the marble cake. He served 1 more piece of the lemon cake than marble cake.

Step-by-step explanation:

A third of 6 is 2 and half of six is 3.

8 0

2 years ago

Pls answer quickly. Thanks!

Gwar [14]

Answer:

the answer is D

Step-by-step explanation:

4 0

3 years ago

A Web music store offers two versions of a popular song. The size of the standard version is 2.4 megabytes (MB). The size of the

ANEK [815]

Answer:

50.mb

Step-by-step explanation:

7 0

3 years ago

I need help!! Find the area of each shaded segment. Round your answer to the nearest 10th

guajiro [1.7K]

Given:

θ = 60°

Radius = 8 in

To find:

The area of the shaded segment.

Solution:

Vertically opposite angles are congruent.

Angle for the shaded segment = 60°

<u>Area of the sector:</u>

$$A=\pi r^2\times \frac{\theta}{360^\circ}$

$$A=3.14 \times 8^2\times \frac{60^\circ}{360^\circ}$

A = 33.5 in²

Area of the sector = 33.5 in²

<u>Area of triangle:</u>

$$A=\frac{1}{2} bh$

$$A=\frac{1}{2} \times 8\times 8$

A = 32 in²

Area of the triangle = 32 in²

Area of segment = Area of sector - Area of triangle

= 33.5 in² - 32 in²

= 1.5 in²

The area of the shaded segment is 1.5 square inches.

8 0

3 years ago

Which of the following ordered pairs is not a solution of the system of inequalities? y > x2 – 4x – 5 y < –x2 – 5x + 6 Que

horrorfan [7]

Answer:

a) (x, y) = (1, 7)

Step-by-step explanation:

Let be the following system of inequalties:

$y > x^{2}-4\cdot x -5$

$y < -x^{2}-5\cdot x +6$

We can find the right option by evaluating each option in the system of inequalities:

a) (x, y) = (1, 7)

$7 > 1^{2}-4\cdot (1) -5$

$7 < -1^{2}-5\cdot (1) +6$

Then,

$7>-8$ (TRUE)

$7$ (FALSE)

(1, 7) is not a solution of the system of inequalities.

b) (x, y) = (1, -7)

$-7 > 1^{2}-4\cdot (1) -5$

$-7 < -1^{2}-5\cdot (1) +6$

Then,

$-7 > - 8$ (TRUE)

$-7< 0$ (TRUE)

(1, -7) is a solution of the system of inequalities.

c) (x, y) = (1, -5)

$-5 > 1^{2}-4\cdot (1) -5$

$-5 < -1^{2}-5\cdot (1) +6$

Then,

$-5 > - 8$ (TRUE)

$-5< 0$ (TRUE)

(1, -5) is a solution of the system of inequalities.

d) (x, y) = (-1, 6)

$6 > (-1)^{2}-4\cdot (-1) -5$

$6$

Then,

$6>0$ (TRUE)

$6 < 12$ (TRUE)

(-1, 6) is a solution of the system of inequalties.

Therefore, we conclude that correct answer is A.

4 0

3 years ago