A truck is 180 inches long.

A person is training for a cross country and manages to run 2 miles in a time of 12 mins what was the runners average velocity i

spin [16.1K]

Answer:

10 miles per hour

Step-by-step explanation:

Average velocity=distance covered/time in hours

Distance=2 miles

time=12minute

change minutes to hour=12/60 =0.2hrs

v=2÷0.2

v=10miles per hour

5 0

3 years ago

Read 2 more answers

Mr. Ramirez burns 236 calories riding his bike each hour. He wants to burn more than 590 calories riding her bike at the same ra

s2008m [1.1K]

Answer:

t > 2.5

Step-by-step explanation:

590/236 = 2.5

t > 2.5

5 0

3 years ago

Does the sample provide strong evidence that the mean weight of the bags is lower than the 35.6 grams listed on the package? Gro

kirill115 [55]

Answer:

As probability of that happening is very small; Yes, 33.6 is less than 35.6 grams because it provide strong evidence that the mean weight of the bags is lower than the 35.6 grams listed on the package.

Step-by-step explanation:

For a normal distribution Z-score

$Z = \frac{X-\mu}{\sigma}$

Given that :

the mean ( $\mu$ ) = 35.6

standard deviation ( $\sigma$ ) = 5.2

sample size (n) = 35

standard error: $\sigma_x = \frac{\sigma}{\sqrt{n}}$

$\sigma_x = \frac{5.2}{\sqrt{35}}$

$\sigma_x = 0.879$

The probability that a random sample of 35 bags has a mean weight of 33.6 grams or less is :

P(X<33.6) = P(Z < - 2.28)

= 0.0114

Conclusion:

As probability of the happening is very small; Yes, 33.6 is less than 35.6 grams because it provide strong evidence that the mean weight of the bags is lower than the 35.6 grams listed on the package.

7 0

4 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is µd =

ahrayia [7]

Answer:

d: 2, 4, -6, 0, -1, -5, 0, 1

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{29}{8}=-0.625$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =3.378$

The next step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.625 -0}{\frac{3.378}{\sqrt{8}}}=-0.523$

And the correct option would be:

a. t = -0.523

Step-by-step explanation:

We assume the following notation:

x=test value after , y = test value before

x: 34 39 28 33 27 23 35 33

y: 32 35 34 33 28 28 35 32

The system of hypothesis for this case is given by:

Null hypothesis: $\mu_y- \mu_x = 0$

Alternative hypothesis: $\mu_y -\mu_x \neq 0$

The first step is calculate the difference $d_i=y_i-x_i$ and we obtain this:

d: 2, 4, -6, 0, -1, -5, 0, 1

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{29}{8}=-0.625$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =3.378$

The next step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.625 -0}{\frac{3.378}{\sqrt{8}}}=-0.523$

And the correct option would be:

a. t = -0.523

5 0

4 years ago

An investment is worth $3 comma 659 in 1992. By 1997 it has grown to $ 6 comma 659. Let y be the value of the investment in the

kakasveta [241]

Answer:

y = 600x + 3659

Step-by-step explanation:

General form of the linear equation:

y = mx + b

Given :

x = 0 represents 1992

x = 0 , y = 3659

So, x value for 1997 becomes:

x = 1997-1992 = 5

at x = 5, y = 6659

Plugging in x = 0, y = 3659 in y = mx+b

3659 = m(0) + b

b = 3659

Plugging in x = 5, y = 6659 and b = 3659

6659 = m(5) + 3659

Solving for m:

m(5) = 6659-3659

5m = 3000

m = 3000/5 = 600

Now plug in the values of unknowns m and b in general equation:

y = 600x + 3659

8 0

3 years ago