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2 years ago

P-3=-4 pls i need to know

Mathematics

2 answers:

rosijanka [135]2 years ago

5 0

Answer:

p = -1

Step-by-step explanation:

p - 3 = -4

+3 +3

------------------

p = -1

fenix001 [56]2 years ago

3 0

Answer: The answer is p = -1.

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Please find the complete question in the attachment file.

$n_1 = 26 \\\\ x_1 = 16.12 \\\\s_1 = 3.58\\\\n_2 = 26\\\\ x_2 = 19.85 \\\\ s_2 = 4.51$

$H_0: u_1 = u_2\\\\H_1: u_1 \neq u_2$

Using formula:

$\to S^{2}_{p}=\frac{S^{2}_{1}(n_1 -1)+ S^{2}_{2}(n_2-1)}{n_1+n_2-2}$

$\to Sp^2 = \frac{((26-1) \times (3.58^2) + (26-1) \times (4.51^2))}{(26+26-2)}$

$= \frac{((25) \times 12.8164 + (25) \times 20.3401 )}{(26+24)}\\\\ = \frac{(320.41 + 508.5025)}{(50)}\\\\ = \frac{(828.9125)}{(50)}\\\\=16.57825$

$\to Sp = 4.0716$

Calculating the value of standard error:

$\to SE = Sp \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}$

$=4.0716 \times \sqrt{\frac{1}{26}+\frac{1}{26}}\\\\=4.0716 \times \sqrt{\frac{1+1}{26}}\\\\=4.0716 \times \sqrt{\frac{2}{26}}\\\\=4.0716 \times \sqrt{\frac{1}{13}}\\\\=4.0716 \times 0.277 \\\\=1.1278332\\\\= 1.1293$