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wlad13 [49]
3 years ago
14

47 POINTS PLZZ HELP ASAP

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

c is the answer

Step-by-step explanation:

so we know one equation

y=6x+15

we need to find the other one

24-10=14

14 miles in 2 hours

7 miles in 1 hour

y=7x+10

henry's ballon begins at 10 miles from the town and is 24 miles from the town in 2 hours

Where henry starts is 10 the y-intercept

look at the slopes

Henry: y=7x+10

Tasha: y=6x+15

Tasha starts farther away

Henry goes farther

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For questions 2-7, solve for x. Round your answer to the nearest tenth.<br> x<br> 11<br> 31
Oksanka [162]

\sin 31^{\circ}=\frac{11}{x}\\\\x=\frac{11}{\sin 31^{\circ}} \approx \boxed{21.4}

3 0
2 years ago
How do round789091 to the nearest ten thousand
n200080 [17]

Answer:

789,091 to the nearest ten thousand is

790,000

7 0
4 years ago
Read 2 more answers
I want 5kg of rice.
nikdorinn [45]

The best possible choice for addition will be given by

a)  Cost of 5 boxes of 1 kg rice = £7

b) Cheapest way to buy 5 kg rice is by buying 2 kg + 2 kg+ 1 kg and the        

    cost is £6.7

What is addition?

Bringing two or more numbers together to find a new total is called addition.

Here,

a) Cost of 1 kg rice = £1.4

   Cost of 5 boxes of 1 kg rice = £1.4 * 5

                                                  = £7

b) Possible ways of buying 5kg rice

1) 1 kg + 1 kg + 1 kg + 1 kg + 1 kg

2) 1 kg + 1 kg + 1  kg + 2 kg

3) 1 kg + 1 kg  + 1.5 kg + 1.5 kg

4) 2 kg + 2 kg + 1 kg

Now

cost of rice in 1) = £(1.40 + 1.40  + 1.40 + 1.40 + 1.40) = £7

cost of rice in 2) = £(1.40 + 1.40  + 1.40 + 2.65) = £6.85

cost of rice in 3) = £(1.40 + 1.40  + 2.05 + 2.05) = £6.9

cost of rice in 4) = £(2.65 + 2.65 + 1.40) = £6.7

Cheapest way to buy 5 kg rice is by buying 2 kg + 2 kg+ 1 kg and the cost is £6.7

To learn more about addition, refer to the link:

brainly.com/question/5982761

#SPJ9

Complete Question

A shop sells three different sized boxes of rice. Nice Rice 1kg £1.4, 1.5 kg

£2.05, 2kg 2.65

a) I want  of rice. I could buy five boxes of size . How much would that cost? b) I could buy  of rice in different ways. How much would it cost to buy  of rice in the cheapest way possible?

4 0
2 years ago
If ∠1 and ∠2 are complementary and m∠1 = 17º, what is m∠2
Romashka [77]

Answer:

m<2 = 73

Step-by-step explanation:

Since <1 and <2 are complementary (which means that they equal 90), all you have to do is subtract 17 from 90 to find your answer:

90 - 17 = 73

thus, m<2 = 73

8 0
3 years ago
1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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