Surface Area of a Sphere = 4π(d/2)²
Let the smaller sphere's diameter be just a sample of 4 units in diameter and let the large spheres diameter be 4 times that of the smaller sphere.
Small Sphere: 4π(4/2)² = 16π units²
Large Sphere: 4π(16/2)² = 256π units²
256π / 16π = 16 times
The large sphere has a surface area 16 times that of the smaller one.
Multiply 2,500 by 1.50 which is B.
Answer:
1. Identify the problem: Packaging boxes use too much material and create waste
2. What are the equations for the volume and surface area of a cube and rectangular prism?
Volume of a cube: Vcube = L x L x L = L3
Surface area of a cube: SAcube = 6 x (L x L) = 6L2
Volume of a rectangular prism: VRP = L x W x H = LWH
Surface area of a rectangular prism: SARP = 2 x (L x W) + 2 x (L x H) + 2 x (W x H) = 2(LW + LH + WH)
3. What is the difference in surface area of the packages below? (Note that they have the same volume.)
SAcube = 6L2
= 6 (20 cm)2
= 2,400 cm2
SARP = 2(LW + LH + WH) = 2 (20cm x 10cm + 20cm x 40cm + 10cm x 40cm) = 2,800 cm2
SARP – SAcube = 2,800 cm2
– 2,400cm2
= 400 cm
Step-by-step explanation:
everything in bold is the answer
Can I please get the Brainlist
Answer:
0.6 or 
Step-by-step explanation:
Using the Pythagorean theorem (
) we get that the hypotenuse is 5.
so the cos V is adjacent over the hypotenuse. so if adjacent is 3 and hypotenuse is 5, the answer is which equals 0.6 in decimal form.
Answer:
A good rule is to change 10 to 15 percent of the water each week. If your tank is heavily stocked, bump that up to 20 percent each week. A lightly stocked aquarium can maybe get by for two to four weeks, but this should be the maximum length of time between water changes.
Step-by-step explanation:
This is the correct answer you want
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