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3 years ago

Put this in least to greatest

Mathematics

1 answer:

ra1l [238]3 years ago

5 0

Answer:

1. Square root of 8 over 2 (1.41)

2. 2

3. Square root of 7 (2.65)

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Katie invested a total of $4000, part at 2% simple interest and part at 3% simple interest. At the end of 1 year, the inves

Fiesta28 [93]

Answer:

$3000

$1000

Step-by-step explanation:

the formula for simple interest = principal x time x interest rate

let the amount invested in the 2% investment be a

let the amount invested in the 3% investment be (4000 - a)

(a x 0.02 x 1) + ([4000 - a] x 0.03 x 1) = $90

0.02a + 120 - 0.03a = 90

Collect like terms and solve for a

0.01a = 30

a = $3000

The amount invested in the 3% investment be (4000 - a) = $4000 - $3000 = $1000

7 0

3 years ago

Plz help, its due today

geniusboy [140]

Answer:

its 55

Step-by-step explanation:

6 0

3 years ago

A. $1,200 B. $1,080 C. $24 D. $810

tangare [24]

Answer:

Option B, $1080

Step-by-step explanation:

Step 1: Identify which option is correct

To find the initial amount of money you need to find the y-int or the value of y when the x value is 0.

So... when the x value is zero on this graph, the y-int or y value is 1080

Answer: Option B, $1080

4 0

4 years ago

Plssss help

svlad2 [7]

Can I see the actual problem

7 0

3 years ago

A manager records the repair cost for 4 randomly selected TVs. A sample mean of $88.46 and standard deviation of $17.20 are subs

WINSTONCH [101]

Answer:

a) The critical value is $z = 2.575$ .

b) The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ . This is our critical value

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

a. Find the critical value that should be used in constructing the confidence interval.

The critical value is $z = 2.575$ .

b. Construct the 99% confidence interval. Round your answer to two decimal places.

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. So, in this problem

$M = 2.575*\frac{17.20}{\sqrt{4}} = 22.15$

The lower end of the interval is the mean subtracted by M. So it is 88.46 - 22.15 = $66.31

The upper end of the interval is the mean added to M. So it is 88.46 - 22.15 = $110.61

The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

5 0

3 years ago