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Nesterboy [21]
3 years ago
7

1. What does it mean that a reflection maps AEFG onto AE'F'G? HELPPP PLEASE❗️❗️❗️‼️‼️

Mathematics
1 answer:
attashe74 [19]3 years ago
8 0

Answer:the answer is app u welcome text me back if i got it wrong armstrongtamarion

Step-by-step explanation:

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I'm confused on how to do this. Please explain step by step. If you respond with just the answer I WILL report you. I would like
Tcecarenko [31]

Answer:

Exact Form:

√2−1

Decimal Form:

0.41421356

…

Step-by-step explanation:

Since  9π/8  is not an angle where the values of the six trigonometric functions are known, try using half-angle identities.

9π/8  is not an exact angle

First, rewrite the angle as the product of  1/2  and an angle where the values of the six trigonometric functions are known. In this case,  9π/8  can be rewritten as

(1/2)*  9π/8 tan ((1/2)*  9π/8)

Use the half-angle identity for tangent to simplify the expression. The formula states that  

tan (0/2)=sin(0)/1+cos(0) sin(9π/4)/1+cos(9π/4)

Simplify

Remove full rotations of  2π  until the angle is between  0  and  2π.

sin(π/4)/1+cos(9π/4)

The exact value of sin(π/4) is √2/2

√2/2/1+cos(9π/4)

Simplify the Denominator

Remove full rotations of  2π  until the angle is between  0  and  2π.√2/2/1+cos(π4)

The exact value of cos(π/4)   is  √2/2.√2/2/1+√2/2

To write  1/1  as a fraction with a common denominator, multiply by  2/2  .√2/2/1/1⋅2/2+√2/2

Write each expression with a common denominator of  2, by multiplying each by an appropriate factor of  1.

Combine.

√2/2/1⋅2/1⋅2+√2/2

Multiply 2 by 1

√2/2/1⋅2/2+√2/2

Combine the numerators over the common denominator.

√2/2/1⋅2+√2/2

Multiply 2 by 1

√2/2/2+√2/2

Multiply the numerator by the reciprocal of the denominator

√2/2  ⋅  2/2+√2

Cancel the common factor of  2  .

Factor out the greatest common factor  2

√2/2⋅1  ⋅  2⋅1/2+√2

Cancel the common factor

√2/2⋅1  ⋅  2⋅1/2+√2

Rewrite the expression.

√2/1  ⋅  1/2+√2

Simplify

Multiply  √2/1  and  1/2+√2

√2/2+√2

Multiply  √2/2+√2  by  2−√2/2−√2

Combine

√2(2−√2)/(2+√2)(2−√2)

Expand the denominator using the FOIL method.

√2(2−√2)/4−2√2+√2⋅2−√2^2

Simplify

√2(2−√2)/2

Apply the distributive property

√2⋅2+√2(−√2)/2

Move  2  to the left of the expression  √2⋅2.

2⋅√2+√2(−√2)/2

Simplify  

√2(−√2)  .

Raise  √2  to the power of  1  .

2⋅√2−(√2^1√2)/2

Raise  √2  to the power of  1  .

2⋅√2−(√2^1√2^1)/2

Use the power rule  a^m  a^n=a^m+n  to combine exponents.

2⋅√2−√2^1+1/2

Add  1  and  1  .

2⋅√2−√2^2/2

Simplify each term.

Multiply  2  by  √2  .

2√2−√2^2/2

Rewrite  √2^2  as  2  .

2√2−1⋅2/2

Multiply  −1  by  2.

2√2−2/2

Reduce the expression by cancelling the common factors.

Factor  2  out of  2√2.

2(√2)−2/2

Factor  2  out of  −2.

2(√2)+2⋅−1/2

Factor  2  out of  

2(√2)+2(−1)2(√2−1)/2

Cancel the common factors.

Factor  2  out of  2  .

2(√2−1)/2(1)

Cancel the common factor.

2(√2−1)/2⋅1

Rewrite the expression.

√2−1/1

Divide  √2−1  by  1  .

√2−1

The result can be shown in multiple forms.

Exact Form:

√2−1

Decimal Form:

0.41421356…

Hope it help. Good luck.

4 0
3 years ago
If the rate , in gallons per minute , continues , approximately how many gallons of water from the hose in 45 minutes ?
navik [9.2K]
Every 5 minutes, you gain 4 gallons. 45/5 = 9, 9x4 equals 36, there would be 36 gallons of water in 45 minutes
3 0
3 years ago
To find the surface area of the pyramid, in square inches, Vikram wrote (33.2) (34.2) + 4 (one-half (34.2) (28.4)). What error d
madam [21]

Answer:

B. He used the wrong expression to represent the area of the base of the pyramid.

Step-by-step explanation:

Given

See attachment for pyramid

Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4

Required

Vikram's error

The surface area of a square pyramid is:

Area = Base\ Area + 4 * Area \triangle

Where

Base\ Area = Length * Length

Base\ Area = 34.2 * 34.2

4 * Area \triangle = 4 * \frac{1}{2} * Base * Height

4 * Area \triangle = 4 * \frac{1}{2} * 34.2 * 28.4

So:

Area = Base\ Area + 4 * Area \triangle

Area = 34.2 * 34.2 + 4 * \frac{1}{2} * 34.2 * 28.4

By comparing the calculated expression with

Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4

Option (b) is correct

3 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 81% of the students were found to be
Dvinal [7]

Answer:

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

Step-by-step explanation:

Let's define the events:

L: The student is proficient in reading

M: The student is proficient in math

The probabilities are given by:

P (L) = 0.81\\P (M) = 0.74\\P (L\bigcap M) = 0.64

P (M\bigcap L^c) = P (M) - P (M\bigcap L) = 0.74 - 0.64 = 0.1\\P (M^c\bigcap L) = P (L) - P (M\bigcap L) = 0.81 - 0.64 = 0.17

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

5 0
4 years ago
What is the quadrilateral and triangle and square
S_A_V [24]
They are parallelogram  hopes that answer your question

5 0
3 years ago
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