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Gnom [1K]
2 years ago
14

Could someone please explain how to solve this equation step by step? -9/2 + 2x+9/2x =-5

Mathematics
1 answer:
telo118 [61]2 years ago
3 0

Answer:

nope sorryyyyy

Step-by-step explanation:

hahahaha

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3(2x + 11) and (3x + 15)(2)
algol [13]

Answer:

3(2x+11)= 6x+33  and (3x+15)(2) = 6x+30

Step-by-step explanation:

Use distributive property to multiply the outside factor to each factor inside the parenthesis.  

3(2x+11)

(3*2x)+(3*11)

6x+33

3 0
3 years ago
Write the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y = -5. Include your work
STALIN [3.7K]
Paralell to 2x+y=-5
means it has same slope
means it is in form
2x+y=c where we have to find c
convert to slope intercept
minus 2x both sides

xint of 2
xint is where th eline crosses the x axis or where y=0, x=2

2(2)+0=c
2(2)=c
4=c


the equation is 2x+y=4
4 0
3 years ago
Divide. Show your work.<br><br> (6x^4-5x^3+6x^2)/2x^2
serg [7]
We can do like we did before, distribute the denominator,

\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}&#10;\\\\\\&#10;3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}&#10;\\\\\\&#10;3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3
6 0
3 years ago
Match the independent variable, dependent variable and constant for the following statement.
den301095 [7]
Independent: cell phone plan
dependent: monthly cost
constant: per month/per minute (money)
5 0
3 years ago
Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.
jek_recluse [69]

Answer:

Choice B: y = 2\, (x - 6)^{2} + 5.

Step-by-step explanation:

For a parabola with vertex (h,\, k), the vertex form equation of that parabola in would be:

\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}.

In this question, the vertex is (6,\, 5), such that h = 6 and k = 5. There would exist a constant a such that the equation of this parabola would be:

y = a\, (x - 6)^{2} + 5.

The next step is to find the value of the constant a.

Given that this parabola includes the point (7,\, 7), x = 7 and y = 7 would need to satisfy the equation of this parabola, y = a\, (x - 6)^{2} + 5.

Substitute these two values into the equation for this parabola:

7 = (7 - 6)^{2}\, a + 5.

Solve this equation for a:

7 = a + 5.

a = 2.

Hence, the equation of this parabola would be:

y = 2\, (x - 6)^{2} + 5.

4 0
3 years ago
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