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Gnom [1K]
3 years ago
14

Could someone please explain how to solve this equation step by step? -9/2 + 2x+9/2x =-5

Mathematics
1 answer:
telo118 [61]3 years ago
3 0

Answer:

nope sorryyyyy

Step-by-step explanation:

hahahaha

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Find the value of each variable in the parallelogram
kompoz [17]

9514 1404 393

Answer:

  k = 7

  m = 8

Step-by-step explanation:

The diagonals bisect each other, so each half is equal to the opposite half.

  k +4 = 11 . . . . down-sloping diagonal

  k = 7

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  m = 8 . . . . up-sloping diagonal

4 0
3 years ago
2. Julio has 1/6 pound of candy. He puts the candy
SashulF [63]

Answer:

4/6

Step-by-step explanation:

(1/6 times 4)make 4 into a fraction and that is 4/1  multyply the numerator and denominator 6x1=6 so 6 is the denominator and 4x1 is 4 so 4 is the numerator so its 4/6

5 0
3 years ago
Which is greater than 1/7 or 4/6
Alex Ar [27]

Answer:

4/6

Step-by-step explanation:

you multiply until both numbers have the same denominator so 1/7 times 6/6 equals 6/42 and multiply 4/6 times 7/7 it would be 28/42 so the answer would be that 4/6 is greater.


5 0
3 years ago
Read 2 more answers
I WILL GIVE 100 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT. Identify all the numbered angles that are congruent to the given
Free_Kalibri [48]

Answer:

Angle 1,4 and 7

Step-by-step explanation:

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4 0
3 years ago
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Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
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