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prisoha [69]
3 years ago
14

Solve P = 8/3 R + 30 for R.

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

R = (3P-30)/8

Step-by-step explanation:

subtract 30 from each side to get:

P-30 = \frac{8}{3}R

multiply each side by \frac{3}{8} to get:

\frac{3}{8} · P - 30 = R

R = (3P-30)/8

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Step-by-step explanation:

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Factor -2.9 out of 8.7b – 11.6. Using gfc or without
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3 years ago
Reduce -56/-70 to lowest terms <br><br> •-2/3<br> •-4/5<br> •4/5<br> •8/10
Kaylis [27]
4/5 is the right answer.....
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Read 2 more answers
its question #2 my son and I cannot figure out how to do this other than dividing. however, when u divide 59 into 422, are you s
anyanavicka [17]
Honestly I can see an argument for 7 shelves or for 8 shelves. 

When you do the calculation; \frac{422}{59}=7.15 You get 7.15 shelves. Clearly you cannot have .15 of a shelf so the logician in me wants to say you need 8 shelves! 

But if the assignment is aimed estimation skills, (Which is what I assume is being implied by the title of the assignment), then the easier calculation of \frac{420}{60}=7 is probably what the teacher was hoping for.

You might have been accidentally been calculating \frac{59}{422} =.139. Remember division is NOT communitive! i.e.1\div2\neq2\div1.

From the image;
The first step was to see that 59 can not go into 4..resulting in the zero above the 4, multiplying 0 by 59 and subtracting 0 from 4. 

The second step begins by bringing down the 2, seeing that 59 can not go into 42..resulting in the zero above the 2, multiplying 0 by 59 and subtracting 0 from 42.

The third step begins by bringing down the 2, seeing that 59 can go into 422 7 times (I tested this on the right by a short multiplication problem)..resulting in the 7 above the 2, multiplying 7 by 59 and subtracting 413 from 42.

This process continues....

8 0
3 years ago
Read 2 more answers
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Answer:

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Because we have two solutions, i know that we are talking about quadratic equations, of the form of:

0 = a*x^2 + b*x + c.

There are two easy ways to see if the solutions of this equation are real or not.

1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).

2) look at the determinant.

The determinant of a quadratic equation is:

D = b^2 - 4*a*c.

if D > 0, we have two real solutions.

if D = 0, we have one real solution (or two real solutions that are equal)

if D < 0, we have two complex solutions.

3 0
3 years ago
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