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ankoles [38]
3 years ago
13

What is the slope of a line parallel to the line y=3x-4=8y+1

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

Answer:  If the original equation is y = 3x -4,  the slope is 3.

Any equation of a line parallel to the line <u>y = 3x -4</u> will have a slope of 3.

Step-by-step explanation:

In slope-intercept form, y =mx + b the coefficient of x, m is the slope.

Here 3 is that value.

It is very unusual to have two equal signs in a question about slope.

I am not sure what to do with the <u><em>=8y + 1</em></u>

Is this supposed to be another equation in the system, missing a term?

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So here are 4 rules when it comes to exponents:

  1. When you raise a power to a power, you really just multiply the exponents: (x^m)^n=x^{m*n}
  2. When you multiply 2 exponents of the same base, you add the exponents together: x^m*x^n=x^{m+n}
  3. When you divide 2 exponents of the same base, you subtract the exponents: \frac{x^m}{x^n}=x^{m-n}
  4. To convert a negative exponent into a positive one, flip it to its reciprocal: x^{-m}=\frac{1}{x^m}\\ \frac{1}{x^{-m}}=\frac{x^{m}}{1}=x^m

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\frac{2x^3y^3}{4y^2}=\frac{1}{2}x^{3-0}y^{3-2}=\frac{1}{2}x^3y

<u>Part B:</u>

(\frac{x^{-8}}{y^{11}})^{-2}=\frac{x^{-8*-2}}{y^{11*-2}}=\frac{x^{16}}{y^{-22}}=\frac{x^{16}y^{22}}{1}=x^{16}y^{22}

<u>Part C:</u>

\frac{(2x^3)(x^4)^2}{8x^{11}}=\frac{(2x^3)(x^{4*2})}{8x^{11}}=\frac{(2x^3)(x^8)}{8x^{11}}=\frac{2x^{3+8}}{8x^{11}}=\frac{2x^{11}}{8x^{11}}=\frac{1}{4}x^{11-11}=\frac{1}{4}x^0=\frac{1}{4}

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