The length of the shorter base is 4 in and the height is: h = 5 in.
If the obtuse angle is 135°, than the sharp angle is 45°.
It means that x = h and a = h + 2 x.
x = 5 and : a = 4 + 2 ·5 = 4 + 10 = 14 in
Area:
A = ( a+ b ) / 2 · h
A = ( 14 + 4 ) / 2 · 5
A = 18 / 2 · 5 = 9 · 5 = 45 in²
Answer: The area of the trapezoid is 45 in².
Answer:
![x=2, y=3, z=4+t](https://tex.z-dn.net/?f=%20x%3D2%2C%20y%3D3%2C%20z%3D4%2Bt)
Step-by-step explanation:
For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:
![u= (u_x, u_y, u_z)= (0,0,1)](https://tex.z-dn.net/?f=%20u%3D%20%28u_x%2C%20u_y%2C%20u_z%29%3D%20%280%2C0%2C1%29)
Or any factor of u but for simplicity let's take the unitary vector.
Then the parametric equations are given by:
![x= P_x + u_x t](https://tex.z-dn.net/?f=%20x%3D%20P_x%20%2B%20u_x%20t)
![y= P_y + u_y t](https://tex.z-dn.net/?f=%20y%3D%20P_y%20%2B%20u_y%20t)
![z= P_z + u_z t](https://tex.z-dn.net/?f=%20z%3D%20P_z%20%2B%20u_z%20t)
Where the point given ![P=(2,3,4)= (P_x , P_y, P_z)](https://tex.z-dn.net/?f=%20P%3D%282%2C3%2C4%29%3D%20%28P_x%20%2C%20P_y%2C%20P_z%29%20)
And then since we have everything we can replace like this:
![x= P_x + u_x t 2+ 0*t = 2](https://tex.z-dn.net/?f=%20x%3D%20P_x%20%2B%20u_x%20t%202%2B%200%2At%20%3D%202)
![y= P_y + u_y t= 3+ 0*t = 3](https://tex.z-dn.net/?f=%20y%3D%20P_y%20%2B%20u_y%20t%3D%203%2B%200%2At%20%3D%203)
![z= P_z + u_z t = 4+ 1t = 4+t](https://tex.z-dn.net/?f=%20z%3D%20P_z%20%2B%20u_z%20t%20%3D%204%2B%201t%20%3D%204%2Bt)
![x=2, y=3, z=4+t](https://tex.z-dn.net/?f=%20x%3D2%2C%20y%3D3%2C%20z%3D4%2Bt)
8*8=64
12/3=4
4*2=8
8*9= 72
72+64=136
136-7=129
your answer is 129
Ugh i’m sorry i hate the links don’t press on them they steal ur info. also i’m really sorry i don’t know the answer i’m just trying to help out!