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ad-work [718]
2 years ago
6

Does anyone know what the answer please?

Mathematics
1 answer:
Tasya [4]2 years ago
5 0
The answer is d........
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SAT math scores have a bell-shaped distribution with a mean of 515 and a standard deviation of 114.
nadezda [96]

Hey there mate :)

Analysis :

401 = 515 - 114 = u - 6

And

173 = 515 - 3.114 = u - 36

=  \frac{p(u - 36 < u < u + 36) - p(u - 6 < u < u + 6)}{2}

=  \frac{99.73percent - 68.21percent}{2}

=  \frac{31.46percent}{2}

= {15.73percent}

Then, calculating,

u - 26 = 515 - 2 \times 114 = 287

And

u + 26 = 515 + 2 \times 114 = 743

Then,

The \: Range = (287,743)

Final Answers :-

<u>1</u><u>5</u><u>.</u><u>7</u><u>3</u><u> </u><u>%</u>

<u>(</u><u>2</u><u>8</u><u>7</u><u>,</u><u>7</u><u>4</u><u>3</u><u>)</u>

~Benjemin360

3 0
3 years ago
The equation is ax+r=7 <br><br>how do I solve for r??
Strike441 [17]
The solution is r= 7/a-x How did i do this?
Your equation is ax+ r=7, so the goal is to isolate the r. You begin by dividing the a from the ax. Remember, what you do to one side, you must do to the other. So you do 7/a, since you can't simplify 7/a, leave it as it is. Next, your equation should look like this x+r=7/a. In order to isolate the r, you move the x to the other side by subtracting, which leaves you with the answer of r= 7/a-x.
Hope this helped!
7 0
3 years ago
Read 2 more answers
Helppppp pleaseeee!!!
Tatiana [17]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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the debate team is showing a video of their recent debate. the first showing begins at 3:15 P.M. The second showing is scheduled
JulijaS [17]
The video will end at 4.20 PM (4.50 - 30 mins). So it starts at 3.15 PM and ends at 4.20 PM. So it is 1 hour and 5 minutes.
4 0
3 years ago
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For each of the following​ situations, indicate what the general impact on the Type II error probability will​ be:
Paraphin [41]

Answer:

Step-by-step explanation:

Hello!

The type II error is committed when you fail to reject a false null hypothesis.

The probability associated with this type of error is symbolized as β.

a. The alpha level is increased.

α and β are two probabilities that are closely related in such a way that if alpha is decreased, beta automatically increases and vice versa when the sample size n is predetermined.

If you increase α then the probability of committing type II error (β) decreases.

b. The "true" population mean is moved farther from the hypothesized population mean.

If the true population mean is moved away from its hypothesized value, then the probabilities of "keeping" a false null hypothesis are bigger.

c. The alpha level is decreased.

This is the inverse situation from a. If you decrease α then, β is automatically increased.

d. The sample size is increased.

If the sample size "n" is left free, it can be shown that by increasing the sample size, both α and β decrease. In practice, α is fixed and β is calculated with several possible sizes of n. Finally choosing as sample size the one that minimizes or gives a reasonable value of β.

I hope it helps!

3 0
3 years ago
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