The correct answer is D) 0,81
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. And we have:
p²+2*p*q+q²= 1 <em>p+q= 1 p=1-q</em>
q= 0.1 p= 1-0.1= 0.9
p²=0.9²= 0.81
I looked it up, and chromosome sounds about right.
If<span> the broad ligament and other supporting ligaments were damaged by infection or injury, this incident may cause to permanent damage or worse even death. This can even lead to infertility because broad ligament is the tissue that stabilizes the uterus, liver and diaphragm.</span>
B and E, since not everyone believes in supernatural beings or the affects of astrological signs
