If darren wants to get 65 balloons, how many yards of string will he need

Casey can buy 3 sandwiches and 5 cups of coffee for $26. Eric can buy 4

ioda

Answer:

Step-by-step explanation:

Let's identify what we are looking for in terms of variables. Sandwiches are s and coffee is c. Casey buys 3 sandwiches, which is represented then by 3s, and 5 cups of coffee, which is represented by 5c. Those all put together on one bill comes to 26. So Casey's equation for his purchases is 3s + 5c = 26. Eric buys 4 sandwiches, 4s, and 2 cups of coffee, 2c, and his total purchase was 23. Eric's equation for his purchases then is 4s + 2c = 23. In order to solve for c, the cost of a cup of coffee, we need to multiply both of those bolded equations by some factor to eliminate the s's. The coefficients on the s terms are 4 and 3. 4 and 3 both go into 12 evenly, so we will multiply the first bolded equation by 4 and the second one by -3 so the s terms cancel out. 4[3s + 5c = 26] means that 12s + 20c = 104. Multiplying the second bolded equation by -3: -3[4s + 2c = 23] means that -12s - 6c = -69. The s terms cancel because 12s - 12s = 0s. We are left with a system of equations that just contain one unknown now, which is c, what we are looking to solve for. 20c = 104 and -6c = -69. Adding those together by the method of elimination (which is what we've been doing all this time), 14c = 35. That means that c = 2.5 and a cup of coffee is $2.50. There you go!

3 0

3 years ago

Find the equation of the line that passes through point (7,5) and (-9,5)

Papessa [141]

Answer:

y = 5

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (7, 5) and (x₂, y₂ ) = (- 9, 5)

m = $\frac{5-5}{-9-7}$ = $\frac{0}{-16}$ = 0

This means the line is horizontal and parallel to the x- axis with equation

y = c

where c is the value of the y- coordinates the line passes through.

The line passes through (7, 5) and (- 9, 5) with y- coordinates 5, thus

y = 5 ← equation of line

4 0

3 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

3 years ago

Please help me with this ty

Andrej [43]

7x12 = 84
So the answer is D.

6 0

2 years ago

Read 2 more answers

(x^3−7x−6) : (x−4)<br> Kan someone solve this for me, and show how to get it?

Vladimir79 [104]

Answer:

x = 3 or x = -1 or x = -2

Step-by-step explanation:

Solve for x:

(x^3 - 7 x - 6)/(x - 4) = 0

Hint: | Multiply both sides by a polynomial to clear fractions.

Multiply both sides by x - 4:

x^3 - 7 x - 6 = 0

Hint: | Factor the left hand side.

The left hand side factors into a product with three terms:

(x - 3) (x + 1) (x + 2) = 0

Hint: | Find the roots of each term in the product separately.

Split into three equations:

x - 3 = 0 or x + 1 = 0 or x + 2 = 0

Hint: | Look at the first equation: Solve for x.

Add 3 to both sides:

x = 3 or x + 1 = 0 or x + 2 = 0

Hint: | Look at the second equation: Solve for x.

Subtract 1 from both sides:

x = 3 or x = -1 or x + 2 = 0

Hint: | Look at the third equation: Solve for x.

Subtract 2 from both sides:

Answer: x = 3 or x = -1 or x = -2

3 0

3 years ago