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3 years ago

Find the surface area of the prism

Mathematics

1 answer:

IRINA_888 [86]3 years ago

6 0

I think the answers 158 m

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Tire rim has a diameter of 15 in. What is the circumference of the tire rim? Use 3.14 for Pi.

Levart [38]

Answer:

The correct option is C. 47.10 inches

Step-by-step explanation:

Diameter of the tire rim is given to be 15 inches

So, The radius of the tire rim will be 7.5 inches

Now, we need to find the circumference of the tire rim

And, The circumference of the tire rim is given by the formula :

Circumference = 2·π × radius

⇒ Circumference of the tire rim = 2 × 3.14 × 7.5

⇒ Circumference of the tire rim = 47.1 inches

Therefore, The correct option is C. 47.10 inches

4 0

3 years ago

Which of the following is a third root of the given complex number.

Leokris [45]

Answer:

The correct option is C.

Step-by-step explanation:

The given complex number is

$z=64(\cos[\frac{\pi}{7}]-i\sin[\frac{\pi}{7}])$

We need to find the third root of the given complex number.

$z^{\frac{1}{3}}=(64(\cos[\frac{\pi}{7}]-i\sin[\frac{\pi}{7}]))^{\frac{1}{3}}$

$z^{\frac{1}{3}}=64^{\frac{1}{3}}(\cos[\frac{\pi}{7}]-i\sin[\frac{\pi}{7}])^{\frac{1}{3}}$

$z^{\frac{1}{3}}=4(\cos[\frac{\pi}{7}]-i\sin[\frac{\pi}{7}])^{\frac{1}{3}}$

De moivre's theorem:

$(\cos\theta+i\sin\theta)^n=\cos n\theta+i\sin n\theta$

where, n is an integer.

Using de moivre's theorem, we get

$z^{\frac{1}{3}}=4(\cos[\frac{\pi}{7}\times \frac{1}{3}]-i\sin[\frac{\pi}{7}\times \frac{1}{3}])$

$z^{\frac{1}{3}}=4(\cos[\frac{\pi}{21}]-i\sin[\frac{\pi}{21}])$

Therefore the correct option is C.

6 0

3 years ago

Read 2 more answers

Measures of each angle given.

daser333 [38]

Does it say if the angles are congruent?

6 0

3 years ago

~please only answer if you know for sure~

NARA [144]

JKL is similar to PQR

so they want PR

JKL is similar to PQR

So PR is similar to JL

And they also give us the sides KL and QR

JKL is similar to PQR

Both of those sides are similar, so we can form a proportion.

$\sf { \frac{PR}{JL} = \frac{QR}{KL} }$

Plug in the numbers:

$\sf { \frac{PR}{6} = \frac{15}{9} }$

Cross multiply:

$\sf{ PR \times 9 = 6 \times 15}$

Isolate PR

$\sf{ PR = \frac{6 \times 15}{9}}$

Simplify it

$\sf{ PR = 10}$

So your final answer is

$\boxed{\bf{10 centimeters}}$

6 0

4 years ago

Read 2 more answers

Denote the set below by set-builder notation, using x as the variable.

Temka [501]

Answer:

C. {x|x is an odd natural number between 1 and 67}

Step-by-step explanation:

B and C is also correct if the natural number is defined to be started with 1: positive integer,

but if it's defined to be non-negative real number then only C

7 0

3 years ago