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pav-90 [236]
2 years ago
9

Which type of evaluation requires that the program be fully implemented before the evaluation can begin

Computers and Technology
1 answer:
Drupady [299]2 years ago
5 0

Answer:

Around the world, there exist many programs and interventions developed to improve conditions in local communities. Communities come together to reduce the level of violence that exists, to work for safe, affordable housing for everyone, or to help more students do well in school, to give just a few examples.

But how do we know whether these programs are working? If they are not effective, and even if they are, how can we improve them to make them better for local communities? And finally, how can an organization make intelligent choices about which promising programs are likely to work best in their community?

Over the past years, there has been a growing trend towards the better use of evaluation to understand and improve practice.The systematic use of evaluation has solved many problems and helped countless community-based organizations do what they do better.

Explanation:

<em>Despite an increased understanding of the need for - and the use of - evaluation, however, a basic agreed-upon framework for program evaluation has been lacking. In 1997, scientists at the United States Centers for Disease Control and Prevention (CDC) recognized the need to develop such a framework. As a result of this, the CDC assembled an Evaluation Working Group comprised of experts in the fields of public health and evaluation. Members were asked to develop a framework that summarizes and organizes the basic elements of program evaluation. This Community Tool Box section describes the framework resulting from the Working Group's efforts.</em>

<em>Despite an increased understanding of the need for - and the use of - evaluation, however, a basic agreed-upon framework for program evaluation has been lacking. In 1997, scientists at the United States Centers for Disease Control and Prevention (CDC) recognized the need to develop such a framework. As a result of this, the CDC assembled an Evaluation Working Group comprised of experts in the fields of public health and evaluation. Members were asked to develop a framework that summarizes and organizes the basic elements of program evaluation. This Community Tool Box section describes the framework resulting from the Working Group's efforts.Before we begin, however, we'd like to offer some definitions of terms that we will use throughout this section.</em>

<em>By evaluation, we mean the systematic investigation of the merit, worth, or significance of an object or effort. Evaluation practice has changed dramatically during the past three decades - new methods and approaches have been developed and it is now used for increasingly diverse projects and audiences.</em>

<em>By evaluation, we mean the systematic investigation of the merit, worth, or significance of an object or effort. Evaluation practice has changed dramatically during the past three decades - new methods and approaches have been developed and it is now used for increasingly diverse projects and audiences.Throughout this section, the term program is used to describe the object or effort that is being evaluated. It may apply to any action with the goal of improving outcomes for whole communities, for more specific sectors (e.g., schools, work places), or for sub-groups (e.g., youth, people experiencing violence or HIV/AIDS). This definition is meant to be very broad</em>

<h2><em>I</em><em> </em><em>HOPE</em><em> </em><em>THIS</em><em> </em><em>HELPS</em><em> </em><em>YOU</em><em> </em><em>ALOT</em><em> </em><em>THANKS</em><em>!</em></h2>
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The groups_per_user function receives a dictionary, which contains group names with the list of users.

Explanation:

The blanks to return a dictionary with the users as keys and a list of their groups as values is shown below :

def groups_per_user(group_dictionary):

   user_groups = {}

   # Go through group_dictionary

   for group,users in group_dictionary.items():

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       # Now add the group to the the list of

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print(groups_per_user({"local": ["admin", "userA"],

       "public":  ["admin", "userB"],

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A standard for compressing music into computer files that can be easily exchanged on the Internet is called a(n) ______. A. musi
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The correct answer is E. MP3

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MP3 (formally MPEG-1 Audio Layer III or MPEG-2 Audio Layer III) is a coding format for digital audio. MP3 as a file format commonly designates files containing an elementary stream of MPEG-1 audio and video encoded data, without other complexities of the MP3 standard. The MP3 format makes it possible to compress a song into a file small enough to be uploaded, downloaded, emailed, and stored on a hard drive.

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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

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3 years ago
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