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wolverine [178]
3 years ago
5

Please help! What values of b and c make △QRS≅△WVX?

Mathematics
2 answers:
BabaBlast [244]3 years ago
7 0

Answer:

b = 12 and c = 5

Step-by-step explanation:

For them to be congruent, the triangles must be congruent by HL, so c+44 = 5b - 11 and b + 34 = 10c - 4. From the first equation, we get that c = 5b - 55. We can substitute this into the second equation and get: b + 34 = 10(5b-55) - 4 = 50b -554 -> 49b =588 -> b  = 12. We use this to solve for c: c = 5b -55 = 5(12) - 55 = 60 - 55 = 5. Therefore, b = 12 and x = 5.

I changed up my solution (sorry for the careless mistake), but I hope this helps! :)

Kobotan [32]3 years ago
3 0

Answer:

12 and 5

Step-by-step explanation:

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Answer:

a) P = 2/7

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In the range of [2,8], we have the following integers which are: 2, 3, 4, 5, 6, 7, 8. So this is a total of 7 integers.

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A<br> Write the equation for<br> line that<br> passes through (1, 1) and (-1,7)
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Answer:y=-3x+4

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(1,1) and (-1,7).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,1), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=1.

Also, let's call the second point you gave, (-1,7), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-1 and y2=7.

Now, just plug the numbers into the formula for m above, like this:

m=

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-1 - 1

or...

m=

6

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So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-3x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(1,1). When x of the line is 1, y of the line must be 1.

(-1,7). When x of the line is -1, y of the line must be 7.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-3x+b. b is what we want, the -3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,1) and (-1,7).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1,1). y=mx+b or 1=-3 × 1+b, or solving for b: b=1-(-3)(1). b=4.

(-1,7). y=mx+b or 7=-3 × -1+b, or solving for b: b=7-(-3)(-1). b=4.

See! In both cases we got the same value for b. And this completes our problem.

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(1,1) and (-1,7)

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y=-3x+4

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