Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
-3x+7<11
-3x<4
x>-4/3
So anything less than or equal to -4/3 does not belong to the solution set.
With your update:
"<span>The options is 4,-1,-5,and 0"
-5 does not belong to the solution set...</span>
I need help my self lol XD
