The best choice is 'C'. If it's 1, 5, and 4, then ideally, in 100 draws, you would expect 10, 50, and 40 ... pretty close to Tyrell's actual experimental results.
The cost of hiring a car for 2 days in 2013 is Rs. 316.8
<h3>How to find the cost of hiring in 2013 ?</h3>
The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013.
Therefore,
cost of hiring for 2018 = Rs. 264
Therefore,
let
cost of hiring in 2013 = 20%(264) + 264
cost of hiring in 2013 = 20 / 100 × 264 + 264
cost of hiring in 2013 = 1 / 5 × 264 + 264
cost of hiring in 2013 = 264 / 5 + 264
cost of hiring in 2013 = 52.8 + 264
cost of hiring in 2013 = 316.8
Therefore, the cost of hiring a car for 2 days in 2013 is Rs. 316.8.
learn more on cost here: brainly.com/question/1663590
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Answer:
a) P(X =16 ) = 0.1853
b) 
= 0.0684
Step-by-step explanation:
GIVEN DATA:
n = 16
p = 0.90
from relation given probabllity can be solve
a)
P(X =16 ) = 0.1853
b) 
= 1 - [ P(X = 13) +P(X = 14) +P(X = 15) +P(X = 16) ]
![= 1 - [ ^{16}C_{13} * 0.90^{13} * (1 - 0.90)^3 +^{16}C_{14} * 0.90^{14} * (1 - 0.90)^2 +^{16}C_{15} * 0.90^{15} * (1 - 0.90)^1 +^{16}C_{16} * 0.90^{16} * (1 - 0.90)^0 ]](https://tex.z-dn.net/?f=%3D%201%20-%20%5B%20%5E%7B16%7DC_%7B13%7D%20%2A%200.90%5E%7B13%7D%20%2A%20%281%20-%200.90%29%5E3%20%2B%5E%7B16%7DC_%7B14%7D%20%2A%200.90%5E%7B14%7D%20%2A%20%281%20-%200.90%29%5E2%20%2B%5E%7B16%7DC_%7B15%7D%20%2A%200.90%5E%7B15%7D%20%2A%20%281%20-%200.90%29%5E1%20%2B%5E%7B16%7DC_%7B16%7D%20%2A%200.90%5E%7B16%7D%20%2A%20%281%20-%200.90%29%5E0%20%5D)
= 0.0684
Answer:
B, C and I think D
Step-by-step explanation:
1. y=7/8x +1
2. y=-10x
3. y=2.5x-7
4. y=1.2x
5. y=-5x-8
