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erica [24]
3 years ago
6

Find the missing leg of a triangle with legs of 7 and a hypotenuse of 10 Help please

Mathematics
2 answers:
ahrayia [7]3 years ago
5 0

Answer:

i believe its 24 in for the other leg

Step-by-step explanation:

algol [13]3 years ago
4 0
I kinda agree w that person ^^^^
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Please help, ill give brainliest, only if its right
alexira [117]

Answer:

it would be in the fourth quadrant, directly underneath where it is now. the base would be c and d

5 0
3 years ago
Jon and Becky measured the circle-shaped part of a sun they drew on the sidewalk.
PIT_PIT [208]

Answer:  The approximate area of the circle is:  <span>3,629.84 cm² .</span>
______________________________________________________
Area of a circle, "A" :  A = π * r² ;

  in which: A = Area of circle ;
               π <span>≈ 3.14 ; 
</span>               r = radius; 

radius of a circle, "r" = d / 2  ;  in which:  "d = diameter" ;

Given "d = 64 cm " ; 
         
                       r = d / 2 = 64 cm / 2 = 32 cm ;
____________________________________________
   So;    A = π * r²  ;
 
            A ≈ (3.14) * (32 cm)² ;
 
            A ≈ (3.14) * (1156 cm²) ;
_____________________________________________

            A  ≈  3,629 .84 cm²  .
_____________________________________________
3 0
3 years ago
Cuántas diagonales tendría una figura de 8 lados?
Oduvanchick [21]

Answer:      20 diagonales

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER
NeTakaya

Step-by-step explanation:

x=90°

SUM OF ALL ANGLES OF PENTAGON =540

90+2(180-Y)+105+113=540

90+360-2Y+105+113=540

488-2Y=540

7 0
3 years ago
Read 2 more answers
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