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Anettt [7]
3 years ago
5

An electrician finds that a 0.6 m length of a certain type of wire has a resistance of 0.13 Ω . What is the total resistance of

the 187 m of this wire he plans to use? Answer in units of Ω
Physics
1 answer:
Tamiku [17]3 years ago
8 0

Answer:

Explanation:

For resistance the formula is as follows

R = ρ L/S

where L is length of the wire , ρ is a constant for a specific material called specific resistance and S is cross sectional area .

For 0.6 m wire , putting the values

.13 = ρ x 0.6 / S

For unknown wire

R = ρ x 187 / S

Dividing the two equations

R / .13 = 187 / .6

R = (.13 x 187) / .6

= 40.5 ohms .

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Answer:

150 N

Explanation:

10*15 = 150 N

4 0
2 years ago
A rocket is launched from rest and moves in a straight line at 30.0 degrees above the horizontal with an acceleration of 35.0 m/
klemol [59]

Answer:

t = 123.59s

Explanation:

For the launch pad section:

Vf = Vo + a*t  where Vo=0.

Vf = 35*25 = 875m/s

The distance traveled during the launch:

d = Vo*t+\frac{a*t^2}{2} = 0+\frac{35*25^2}{2} = 10937.5m

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

\Delta Y = Vo*sin(30)*t - \frac{g*t^2}{2}

-d*sin(30) = Vo*sin(30)*t - \frac{g*t^2}{2}  where d= 10937.5m; Vo=875m/s.

Solving for t:

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t_{total} = t_{launch}+t_{projectile}=25+98.59 = 123.59s

6 0
3 years ago
3.
Greeley [361]

Answer:

90 m/s

8100 m

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v₀ = 0 m/s

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v = at + v₀

v = (0.5 m/s²) (180 s) + 0 m/s

v = 90 m/s

Δx = v₀ t + ½ at²

Δx = (0 m/s) (180 s) + ½ (0.5 m/s²) (180 s)²

Δx = 8100 m

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