The dimensions of a 4−cm by the 4−cm rectangle are multiplied by 1/2 (as a fraction). How is the area of the rectangle affected?
2 answers:
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Lesly got 14 answers correctly.
- Let the correct answers be C.
- Let the incorrect answers be I.
<u>Given the following data:</u>
- Total number of questions = 30 questions.
- Ratio of C to I = 7 : 8
- C to I = 7 + 8 = 15
To find the number of answers she got correctly;
×
×
<em>Correct answers, C </em><em>= </em><em>14 answers</em>
Therefore, Lesly got 14 answers correctly.
Read more: brainly.com/question/24613908
We assume that the dimension 5 has units of feet.
The area of each triangle will be
A = (1/2)bh
where b=2×(5 ft), h=(5 ft)tan(54°)
Then
A = (1/2)(2×5 ft)(5 ft)(tan(54°)
A = 25×tan(54°) ft²
There are 5 such triangles making up this pentagon, so the total area is
total area = 5×25×tan(54°) ft² ≈ 172 ft²
The area of each triangle will be
A = (1/2)bh
where b=2×(5 ft), h=(5 ft)tan(54°)
Then
A = (1/2)(2×5 ft)(5 ft)(tan(54°)
A = 25×tan(54°) ft²
There are 5 such triangles making up this pentagon, so the total area is
total area = 5×25×tan(54°) ft² ≈ 172 ft²