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luda_lava [24]
3 years ago
8

The product of 14 and g =​

Mathematics
1 answer:
zepelin [54]3 years ago
7 0
14xg=14g
Hope it helps
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Triangle FGH is similar to triangle A B C
asambeis [7]

Answer:

x is 12

Step-by-step explanation:

» From scalar properties:

{ \tt{ \frac{FG}{FH} =  \frac{AB}{AC}  }} \\  \\ { \tt{ \frac{9}{6} =  \frac{18}{x}  }} \\  \\ { \tt{x =  \frac{18 \times 6}{9} }} \\  \\ { \boxed{ \tt{ \: x = 12 \: }}}

6 0
3 years ago
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Prove that the value of the expersion y^2-10y+30 can only be a positive number
sergeinik [125]

Answer:

  • See below

Step-by-step explanation:

  • y² - 10y + 30 =
  • y² - 10y + 25 + 5 =
  • (y - 5)² + 5

<u>Since (y - 5)² ≥ 0, the expression above is positve:</u>

  • (y - 5)² + 5 ≥ 5
5 0
3 years ago
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Licemer1 [7]
The answer is A. Even though it have a positive 3, the horizontal shift is opposite of what it is
4 0
3 years ago
Tommy's bank requires a $150
Dafna1 [17]

Answer:

$27

Step-by-step explanation:

I really don't know but my beest guess would be $27 to get back to $150.

8 0
3 years ago
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(−4 + 5) − (6 + 7) = x x 0
weeeeeb [17]

1

Add the numbers

(

−

4

+

5

)

−

(

6

+

7

)

=

0

({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}

(−4+5)−(6+7)=xx0

(

1

)

−

(

6

+

7

)

=

0

({\color{#c92786}{1}})-(6+7)=xx^{0}

(1)−(6+7)=xx0

2

Add the numbers

1

−

(

6

+

7

)

=

0

1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

1−(6+7)=xx0

1

−

(

1

3

)

=

0

1-({\color{#c92786}{13}})=xx^{0}

1−(13)=xx0

3

Multiply the numbers

1

−

1

⋅

1

3

=

0

1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

−

1

3

=

0

1{\color{#c92786}{-13}}=xx^{0}

1−13=xx0

4

Subtract the numbers

1

−

1

3

=

0

{\color{#c92786}{1-13}}=xx^{0}

1−13=xx0

−

1

2

=

0

{\color{#c92786}{-12}}=xx^{0}

−12=xx0

5

Combine exponents

−

1

2

=

0

-12={\color{#c92786}{xx^{0}}}

−12=xx0

−

1

2

=

1

-12={\color{#c92786}{x^{1}}}

−12=x1

Show less

Solution

−

1

2

=

1

3 0
3 years ago
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