Question

Question 2-4 please

Answer 1

Answer:

Step-by-step explanation:

2) a) You have to find the area of semicircle.

r = d/2 = 12/2 = 6 mm

Area of semicircle = $\frac{1}{2}\pi r^{2}$

                              $= \frac{1}{2}*3.14*6*6\\\\= 3.14*3*6\\\\= 56.52 mm^{2}$

b) r = 10 cm

Area of quadrant = $\frac{1}{4}\pi r^{2}$

                             $= \frac{1}{4}*3.14*10*10\\\\=3.14*5*5\\\\= 78.5 cm^{2}$

3) d = 10 m

r = d/2 = 10/2 = 5 m

Area of circular garden = πr²

                                       = 3.14 * 5 * 5

                                       = 78.5 m²

Area of rectangular pool = 8 * 6 = 48 m²

Area of the garden covered in grass = area of the circular garden - area of pool

   = 78.5 - 48

   = 30.5 m²

4) a) r = 60 cm

Area of the top of the circular table = πr²

             = 3.14 * 60 *  60

            = 11304 cm²

diameter of base = 30 cm

r = 30/2 = 15 cm

Area of circular base = 3.14 * 15 * 15

                                   = 706.5 cm²