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Ludmilka [50]
2 years ago
11

PLEASE HELP URGENT WILL MARK AS BRAINLIEST PLUS POINTS!!

Mathematics
2 answers:
bogdanovich [222]2 years ago
8 0

Answer:

x = 3.5

Step-by-step explanation:

i don't really know how to explain it but that is the answer btw love ur username

Irina-Kira [14]2 years ago
3 0
It think I would be 4.5 if it’s the same order as the left side
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x=10

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Step-by-step explanation:

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X+4/2=13 whats x equal
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HELP ASAP! PLEASE WILL MARK CORRECT ANSWER BRAINLIEST! I NEED TO GET IT DONE ASAP 25 POINTS
Aleks [24]

Answer:

  6/7

Step-by-step explanation:

If you want the slope of the line on a graph when x is the independent variable, then solve for y:

  -28y = -24x +14 . . . . . . . . . . . subtract the x-term

  y = (-24/-28)x +14/(-28) . . . . . divide by the y-coefficient

  y = 6/7x -1/2

The "rate of change" is the coefficient of x, 6/7.

6 0
3 years ago
Read 2 more answers
Could someplease explain the whole problem? For the first part my the answer I got was x= .618, -.618, and <img src="https://tex
algol13

9514 1404 393

Answer:

  a) x = (√5 -1)/2 ≈ 0.618034

  b) 1/x = (√5 +1)/2 ≈ 1.618034

Step-by-step explanation:

<u>Given</u>:

  x/(1 -x) = 1/x

<u>Find</u>:

  Exactly, and as a decimal approximation, ...

  a) x, using the quadratic formula

  b) 1/x

<u>Solution</u>:

a) We can multiply the given equation by x(1 -x) to obtain ...

  x² = 1 -x

  x² +x -1 = 0 . . . . . . add x-1

The coefficients for use in the quadratic formula are a=1, b=1, c=-1. The solution using the quadratic formula is ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-1)}}{2\cdot1}=\dfrac{-1\pm\sqrt{5}}{2}

We are only interested in the positive solution, which is ...

  \boxed{x=\dfrac{\sqrt{5}-1}{2}\approx0.618034}

__

b) The quadratic we developed in the first part can be rearranged like this:

  x² +x = 1 . . . . . . add 1 to both sides

  x(x +1) = 1 . . . . . factor out x

  x +1 = 1/x . . . . . .divide by x

Then to find the value of 1/x, we simply need to add 1 to the value of x we have:

  \dfrac{1}{x}=\dfrac{\sqrt{5}-1}{2}+1=\dfrac{\sqrt{5}-1}{2}+\dfrac{2}{2}=\dfrac{\sqrt{5}-1+2}{2}\\\\\boxed{\dfrac{1}{x}=\dfrac{\sqrt{5}+1}{2}\approx1.618034}

5 0
2 years ago
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