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Alik [6]
3 years ago
15

Given: 2x^2+ 32x + 16 = 0

Mathematics
1 answer:
Nataly [62]3 years ago
3 0

Answer:

Step 3: x² + 6x + 64 = -8 + 64

Step-by-step explanation:

At step 3 add 64 on both sides to complete the square.

so x² + 6x = -8

becomes x² + 6x + 64 = -8 + 64 when 64 is added both sides giving us step 3.

continuing from there, we get

x² + 6x + 64 = 56

we then use a² + 2ab + b² = (a + b)² on the left side to get

(x + 8)² = 56 (solve the equation for x)

by taking the root on both sides

√(x + 8)² = √56

x + 8 = +- 2√14 (separate the equations

x + 8 = 2√14

x + 8 = -2√14

Solving for x

x = 2√14 - 8 or x = -2√14 - 8

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