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DiKsa [7]
3 years ago
15

While Akira was visiting her sister in Weston, she bought a toy rocket that was marked down 50% from an original price of $40. I

f the sales tax in Weston is 5%, what was the total cost of the toy rocket?
Mathematics
1 answer:
maw [93]3 years ago
5 0

Answer:

me when I

Step-by-step explanation:

A

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Which fraction is between -5/8 and -1/2​
Rzqust [24]

Answer:

The answer is −1.125...

Step-by-step explanation:

Hope this helps! :)

6 0
3 years ago
What is the area of a rectangle with side lengths of 1/2 and 2/3
ololo11 [35]

Answer:

2/6 square units

Step-by-step explanation:

What is the area of a rectangle with side lengths of 1/2 and 2/3

Step one:

given data

L= 1/2 units

W=2/3 units

Step two:

Area= L*W

substitute

Area= 1/2*2/3

Area=2/6 square units

8 0
2 years ago
87/80 into a mixed number in lowest terms no links or ill report.
svp [43]

Answer:

1   7/80

Step-by-step explanation:

1 and 7 over 80

4 0
3 years ago
I’m so confused I need help please!!
shutvik [7]

Answer:

5. 9 8. 2\sqrt{10}

Step-by-step explanation:

a²+b²=c²

so for #5 12²+b²=15²

144+b²=225 (subtract 144 from both sides)

b²=81

b=9

For #8

9²+b²=11²

81+b²=121 (subtract 81 from both sides)

b²=40

b=\sqrt{40}

\sqrt{40}=

2\sqrt{10}

6 0
3 years ago
Read 2 more answers
Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

                       = \frac{1}{2}(3)(3)

                       = 4.5 units²

Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
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