Answer:
Step-by-step explanation:
Let the larger number = x
Let the smaller number = y
x = 2*y + 8
x * y = 234 Put the first equation into the second.
(2y + 8)*y = 234 Remove the brackets
2y^2 + 8y = 234 Subtract 234 from both sides
2y^2 + 8y - 234 =0 Factor out 2
2(y^2 + 4y - 117) = 0 Divide by 2
y^2 + 4y - 117 = 0
(y + 13)(y - 9)
y = 9 is one answer
x * y = 234
x * 9 = 234 Divide by 9
x = 234/9
x = 26
The two numbers are 9 and 26
Answer:
Its D (600,000)
Step-by-step explanation:
Took the test
B = 4
a=2
b=4
c=2
it’s just solving simultaneous equations
Looks more like Trig than Algebra II
They want us to apply the sum angle formula to 
5π/6 is 150°; I find it easier to think in degrees.
When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.
The sine sum angle formula is


We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2


Third choice
Answer:
2. you can use the formula y2-y1/x2-x1
4-(-6)/1-(-2) = 10/3