Question

i need help with a few questions please. write the equation of the line that is parallel to the line whose equation is y = -4 and that passes through the point (1, 5). a. y=-5 b. y=-4 c.y=1 d. y=5 a line contains the point (–3, 4). if the slope of the line is -2/3, write the equation of the line using slope intercept form. a. y = -2/3x 2 b. y = -2/3x 4 c. y = 3/2x 2 d. y = -2/3x - 3 write the equation of the perpendicular bisector of rs. point r is located at (–1, 3), and point s is located at (3, 1). a. y = -1/2x 2 b. y = -1/2x 3 c. y = 2x - 5 d. y = 2x

Answer 1

1.) Parallel lines has equal slopes. Line y = -4 has a slope of 0.
Required equation is y - y1 = 0
y - 5 = 0
y = 5

2.) Required equation is y - y1 = m(x - x1); where m is the slope and (x1, y1) = (-3, 4)
y - 4 = -2/3(x - (-3))
y - 4 = -2/3(x + 3)
y - 4 = -2/3 x - 2
y = -2/3 x - 2 + 4
y = -2/3 x + 2