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zavuch27 [327]
2 years ago
8

You start driving east for 12 miles, turn left, and drive north for another 10 miles. At the end of driving, what is your straig

ht line distance from your starting point? Round to the nearest tenth of a mile.
Mathematics
2 answers:
Dvinal [7]2 years ago
8 0

Answer:

17.2

Step-by-step explanation:

(14)2+(10)2=

 c2\,\,c^{2}c2

Use the Pythagorean Theorem.

196+100=196+100=196+100=

 c2\,\,c^{2}c2

Simplify.

296=296=296=

 c2\,\,c^{2}c2

Simplify.

±296=\pm\sqrt{296}=±296

​=

 c2\,\,\sqrt{c^{2}}c2

​

Square root both sides.

17.204650...=17.204650...=17.204650...=

 c\,\,cc

Simplify. Ignore negative root, as length must be positive.

17.2≈17.2\approx17.2≈

 c\,\,cc

Round to the nearest tenth.

Mila [183]2 years ago
6 0

Answer:

15.6=c

Step-by-step explanation:

(12)^2+(10)^2=c^2

144+100=c^2

244=c^2

square root of both sides=244= square root c^2

15.620499=c

15.6=c

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If a store had 330 video games, and 47% of the games were for Xbox, and 53% were for ps4, then how many xbox and ps4 games are i
Bingel [31]

Answer:

The number of games for Xbox is about 155

The number of games for PS4 is about 175

Step-by-step explanation:

Let us find the numbers of games for Xbox and for PS4 game

∵ There are 330 video games in the store

∵ 47% of them were for Xbox

- Multiply 47% by 330

∴ The number of games for Xbox = 47% × 330

∵ 47% = \frac{47}{100}

∴ The number of games for Xbox = \frac{47}{100} × 330

∴ The number of games for Xbox = 155. 1

∴ The number of games for Xbox ≅ 155

∵ 53% of them were for PS4

- Multiply 53% by 330

∴ The number of games for PS4 = 53% × 330

∵ 53% = \frac{53}{100}

∴ The number of games for PS4 = \frac{53}{100} × 330

∴ The number of games for PS4 = 174.9

∴ The number of games for PS4 ≅ 175

4 0
3 years ago
What does 1/10 of 3000 equal?
arsen [322]
Answer:-
1/10×3000
=300
4 0
3 years ago
Read 2 more answers
Jake is using a horse trailer to take his horses to his new ranch. 1 Horse= 1,200 lb Trailer= 2,700 lb Jake's truck can tow a ma
Kitty [74]

Answer:

Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

Step-by-step explanation:

Given:

Weight of 1 horse = 1,200 lb

Weight of trailer = 2,700 lb

Jacks'truck can tow a maximum of 5000 pounds.

To find the maximum number of horses Jack can take in his trailer without going over the maximum weight his truck can tow.

Solution:

Let the maximum number of horses that Jack can take be = x

Using unitary method to find weight of x horses.

If 1 horse weights = 1,200 lb

Then x horses will weight in lbs = 1,200\times x = 1,200x

Total weight of horses and trailer in lbs = 1200x+2700

Since the maximum weight the truck can tow = 5,000 lb, so the inequality can be given as:

1200x+2700\leq5000

Subtracting both sides by 2700.

1200x+2700-2700\leq5000-2700

1200x\leq2300

Dividing both sides by 1200.

\frac{1200x}{1200}\leq\frac{2300}{1200}

x\leq1.91

From the inequality solution for x, we can conclude that Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

3 0
3 years ago
(3/8+2/3)+1/3 what would it be
sergij07 [2.7K]

Answer:

1.375 or 1/38

Step-by-step explanation:

(3/8+2/3)+1/3

(1.04166666667)+1/3

1.375 or 1 3/8

8 0
2 years ago
Find the sum of the polynomials.
attashe74 [19]
=(3a-4a-3a)+(2b+6b-2b)+(-7c+9c-7c)
=-4a+6b-5c #
3 0
3 years ago
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