Answer:
x > 1/5
Step-by-step explanation:
All of these three triangle inequalities must be satisfied:
AB +BC > AC
BC +CA > BA
CA +AB > CB
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Taking these one at a time, we have ...
AB +BC > AC
3x +4 + 2x +5 > 4x
x +9 > 0 . . . . . subtract 4x
x > -9
__
BC +CA > BA
2x +5 + 4x > 3x +4
3x > -1 . . . . . . subtract 3x+5
x > -1/3 . . . . . divide by 3
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CA + AB > CB
4x + 3x +4 > 2x +5
5x > 1 . . . . . . subtract 2x+4
x > 1/5
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The only values of x that satisfy all of these inequalities are those such that ...
x > 1/5
Is this the entire question?
Answer:

Explanation:
From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses
What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin
For four throws, it means all four are heads or all four are tails
If all four are heads, we have the probability of this happening as:

if all four are tails, we have the probability as:

Now, the probability of either heads or all tails after 4 tosses will be:
C- in the table every ratio y/x is equal so the relationship is proportional