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Tanzania [10]
3 years ago
10

Select the equation of a straight line that is parallel to the line 4y = 3x + 5

Mathematics
1 answer:
insens350 [35]3 years ago
8 0

Answer:

One equation can be y = 3/4X +2

Step-by-step explanation:

Any equation that has a slope of 3/4 will be parallel to the line 4Y = 3X + 5 because the slope is the same. This can also be shown visually using any graphing calculator.

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What is the median of the following numbers: 120, 35, 42, 119, 120.5, 99, 72 ? *
Roman55 [17]

Answer:

the median is 99

Step-by-step explanation:

(lowest) 35, 42, 72, <u>99</u>, 119, 120, 120.5 (highest)

the median is the middle #

the middle # is 99

6 0
3 years ago
PJ is Decorating Pupcakes for Rocky´s Birthday Party. Her Color Scheme is Black, Purple, and Green. She Will use This Spinner to
Inga [223]
The answer to your question is C.
3 0
2 years ago
Read 2 more answers
If cos(x) = Three-fourths and tan(x) &lt; 0, what is cos(2x)?
makvit [3.9K]

Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

\sin^2(x) + \cos^2(x) = 1sin

2

(x)+cos

2

(x)=1

So we have:

\sin^2(x) + (1/4)^2 = 1sin

2

(x)+(1/4)

2

=1

\sin^2(x) + 1/16= 1sin

2

(x)+1/16=1

Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

2

(x)=15/16

Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

tan(x) < 0

It means that:

sin(x) < 0

So, we have:

\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

15

/4

sin(2x) is then calculated as:

\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)

So, we have:

\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗

4

15

∗

4

1

This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

6 0
2 years ago
Read 2 more answers
What is the answer to 5/12 x6
tester [92]

Answer:

2.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A rectangular garden measures 40 yards by 35 yards. a lawn of uniform width surrounds the garden and has an area of 316 square y
timofeeve [1]
The lawn area of uniform width can be written as follows:
 A = (40 + 2x) * (35 + 2x) - (40) * (35)
 Where,
 x: width of the lawn
 Substituting the value of the area we have:
 316 = (40 + 2x) * (35 + 2x) - (40) * (35)
 Rewriting:
 316 = 1400 + 80x + 70x + 4x ^ 2 - 1400
 Rewriting we have:
 4x ^ 2 + 150x - 316 = 0
 Solving the polynomial we have:
 x1 = - 79/2
 x2 = 2
 Taking the positive root we have that the grass width des:
 x = 2 yards
 Answer:
 
The width of the lawn that surrounds the garden is:
 
x = 2 yards
5 0
3 years ago
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