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dusya [7]
2 years ago
7

Converting from vertex to standard form

Mathematics
1 answer:
stich3 [128]2 years ago
6 0

Answer:

Step-by-step explanation:

y = (x+1)² - 3

 = (x²+2x+1)-3

 = x²+2x-2

:::::

y = (x-2)² + 3

 = (x²-4x+4) + 3

 = x²-4x+7

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Find the value of x.<br> A<br> B<br> X<br> 6<br> 3<br> 2<br> D<br> x = [?]<br> C
GrogVix [38]

Answer:

Step-by-step explanation:

7 0
2 years ago
Not sure of this one. can an.expert help
kifflom [539]

How to get answer by JKismyhusbandbae: To get the answer you would multiply

Pi(3.14) times Radius which is R otherwise 80 square times H which is height 1.3.

It will need around 26138.050... and more it is not a repeating decimal I just simplified it.

6 0
3 years ago
If I put a different sticker on the 30th, 50th, and 60th pages will any of the first 600 pages have all 3 stickers?
icang [17]

Answer:

so the which page that will have the 3 sticker, we must solve the least common multiple of 30, 50, 60. A common multiple is a number that is a multiple of two or more numbers. The common multiples of 3 and 4 are 0, 12, 24, ....

The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.

so the least common multiple of 30, 50 and 60 is 300. so the page that will have 3 stickers is 300th page

Step-by-step explanation:

8 0
3 years ago
Please answer the top half ASAP I need it in 2h please
NeTakaya

Answer:

  1. 4/7
  2. 6/11
  3. 12/17
  4. 19/30
  5. 10/17
  6. 7/15
  7. 11/28
  8. 8/21
  9. 7/3
  10. 23/49
  11. 3/7
  12. 1/2
  13. 4/7
  14. 5/22
  15. 3/7
  16. 3/4
  17. 1/3
  18. 1/10
  19. 3/8
  20. 1/2
  21. 3/8
  22. 4/7
  23. 65/168
  24. 8/21
  25. 40/63
  26. 4/3
  27. 1/2
  28. 9/7
  29. 9/5
  30. 21/44
4 0
3 years ago
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv
kari74 [83]
The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

The mass of the particles moving in river is proportional to the sixth power of 2, or 2^6 = 64 miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship x * 2^6 = k, for some constant k. 

For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

So, the key here is proportional. We can set up two proportions and cross multiply.

\dfrac{x}{2^6} =  \dfrac{15x}{y^6}  \\ (x)(y^6)=(2^6)(15x)

Cancelling our x's (because we don't need to solve for them), we have

y^6 = 15(2^6) = 15(64)=960

To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

\sqrt[6]{y^6} =  \sqrt[6]{960}

Using a calculator, we see that \sqrt[6]{960} = 3.14 \ miles \ per \ hour.
6 0
3 years ago
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