Answer:
C
Step-by-step explanation:
Try it.
Answer:
The class average is 83.6
Step-by-step explanation:
:D
Answer:
The answer is

Step-by-step explanation:
To find an equation of a line given the slope and a point we use the formula

where
m is the slope
( x1 , y1) is the point
From the question the point is (3, -10) and the slope 4
We have

We have the final answer as

Hope this helps you
Answer:
4185
Step-by-step explanation:
A culture of bacteria grows exponentially according to the following general exponential growth function;
where;
p(t) is the population at any given time t.
p(0) is the initial population
k is the growth constant
From the information given we have;
p(0) = 1500
at t = 5, p(t) = 2300; p(5) = 2300
We shall use this information to determine the value of k;

Divide both sides by 1500;

Therefore, the population of the bacteria at any time t is given by;
