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faust18 [17]
3 years ago
15

HELP!!

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0

Answer:

I got the correct answer is 110

Step-by-step explanation:

i hope its help

lapo4ka [179]3 years ago
4 0

Answer:

110 offices

Step-by-step explanation:

you take 66 divided by 60% that is how you get 110

You might be interested in
Y=2x+9 what the answer
tekilochka [14]

Answer:

x=Y/2−9/2

Step-by-step explanation:

please mark brainliest :)

8 0
3 years ago
Simplify the given expression 8x^2-8/ x / 8(x^2 + 8)/26x^2 - 31x
notsponge [240]

Answer:

-x • (x2 - 208x + 814)

 ——————————————————————

           26          

Step-by-step explanation:

Step  1  :

           x2 + 8

Simplify   ——————

             26  

Polynomial Roots Calculator :

  Find roots (zeroes) of :       F(x) = x2 + 8

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  8.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,4 ,8

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        9.00      

     -2       1        -2.00        12.00      

     -4       1        -4.00        24.00      

     -8       1        -8.00        72.00      

     1       1        1.00        9.00      

     2       1        2.00        12.00      

     4       1        4.00        24.00      

     8       1        8.00        72.00      

Polynomial Roots Calculator found no rational roots

Equation at the end of step  1  :

             8     (x2+8)

 ((8•(x2))-((— ÷ 8•——————)•x2))-31x

             x       26  

:

           8

Simplify   —

           x

Equation at the end of step  2  :

             8     (x2+8)

 ((8•(x2))-((— ÷ 8•——————)•x2))-31x

             x       26  

        8      

Divide  —  by  8

        x      

             1 (x2+8)

 ((8•(x2))-((—•——————)•x2))-31x

             x   26  

Equation at the end of step  4  :

                 (x2 + 8)            

 ((8 • (x2)) -  (———————— • x2)) -  31x

                   26x                

Dividing exponential expressions :

 x2 divided by x1 = x(2 - 1) = x1 = x

Equation at the end of step  5  :

                x • (x2 + 8)      

 ((8 • (x2)) -  ————————————) -  31x

                     26          

Equation at the end of step  6  :

          x • (x2 + 8)      

 (23x2 -  ————————————) -  31x

               26          

Rewriting the whole as an Equivalent Fraction :

  Subtracting a fraction from a whole

Rewrite the whole as a fraction using  26  as the denominator :

            23x2     23x2 • 26

    23x2 =  ————  =  —————————

             1          26    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

    Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

23x2 • 26 - (x • (x2+8))      -x3 + 208x2 - 8x

————————————————————————  =  ————————————————

           26                       26        

Equation at the end of step  7  :

 (-x3 + 208x2 - 8x)    

 —————————————————— -  31x

         26            

Rewriting the whole as an Equivalent Fraction :

Subtracting a whole from a fraction

Rewrite the whole as a fraction using  26  as the denominator :

          31x     31x • 26

   31x =  ———  =  ————————

           1         26    

Pulling out like terms :

   Pull out like factors :

  -x3 + 208x2 - 8x  =   -x • (x2 - 208x + 8)  

Trying to factor by splitting the middle term

     Factoring  x2 - 208x + 8  

The first term is,  x2  its coefficient is  1 .

The middle term is,  -208x  its coefficient is  -208 .

The last term, "the constant", is  +8  

Multiply the coefficient of the first term by the constant   1 • 8 = 8  

Find two factors of  8  whose sum equals the coefficient of the middle term, which is   -208 .

     -8    +    -1    =    -9  

     -4    +    -2    =    -6  

     -2    +    -4    =    -6  

     -1    +    -8    =    -9  

     1    +    8    =    9  

     2    +    4    =    6  

     4    +    2    =    6  

     8    +    1    =    9  

Adding fractions that have a common denominator :       Adding up the two equivalent fractions

-x • (x2-208x+8) - (31x • 26)     -x3 + 208x2 - 814x

—————————————————————————————  =  ——————————————————

             26                           26        

Pulling out like terms :

10.1     Pull out like factors :

  -x3 + 208x2 - 814x  =   -x • (x2 - 208x + 814)  

Trying to factor by splitting the middle term

10.2     Factoring  x2 - 208x + 814  

The first term is,  x2  its coefficient is  1 .

The middle term is,  -208x  its coefficient is  -208 .

The last term, "the constant", is  +814  

Multiply the coefficient of the first term by the constant   1 • 814 = 814  

Find two factors of  814  whose sum equals the coefficient of the middle term, which is   -208 .

     -814    +    -1    =    -815  

     -407    +    -2    =    -409  

     -74    +    -11    =    -85  

     -37    +    -22    =    -59  

     -22    +    -37    =    -59  

     -11    +    -74    =    -85  

     -2    +    -407    =    -409  

     -1    +    -814    =    -815  

     1    +    814    =    815  

     2    +    407    =    409  

     11    +    74    =    85  

     22    +    37    =    59  

     37    +    22    =    59  

     74    +    11    =    85  

     407    +    2    =    409  

     814    +    1    =    815  

5 0
3 years ago
I need help with this problem, the link is below!
lilavasa [31]
<h3>Answer:</h3>

m∠QSW < m∠WQS

<h3>Explanation:</h3>

The question is asking which angle is larger, the one at vertex S or the one at vertex Q? You are expected to understand how angles are named and how angle measure works.

Angles are named by listing points on the rays that make them up, with the vertex point in the middle of the list. ∠QSW is the angle whose vertex is at S. (Since there is only one angle with its vertex at S, it could also be called ∠S.) The letters Q and W help you identify that rays SQ and SW form the sides of the angle.

Likewise, ∠WQS is the angle whose vertex is at Q. It could also be called ∠Q without any confusion. The other letters in the name tell you that rays QW and QS are the sides of the angle.

When the rays that make the sides of an angle are closer together, the angle has a smaller measure.

In a triangle, there are a several different ways to determine which of the angles is larger.

  • the larger angle will be opposite the longer side
  • the base point of an altitude line will be closer to the larger (acute) angle
  • the rays that make up the larger angle will be farther apart (at some given radius from the vertex)
  • relative to a perpendicular bisector between the vertices, the vertex of the third angle will be on the side closer to the larger angle (another way to say the relationship of the second point above)

_____

<em>Your triangle</em>

Line segment QW (opposite ∠S) is shorter than line segment SW (opposite ∠Q) so m∠S < m∠Q.

A line segment drawn from W perpendicular to QS is closer to Q, so ∠Q is the larger angle.

Thus we must conclude the measure of ∠QSW is less than the measure of ∠WQS:

... m∠QSW < m∠WQS

_____

<em>Comment on appearances</em>

Here, you're specifically told to go by the appearance of the angles. In most cases, you cannot, as the figures are rarely drawn to scale, and are often drawn to be intentionally misleading.

7 0
3 years ago
5x + 2y = 7<br> Solve for y
nekit [7.7K]

The correct answer is attached below:

8 0
3 years ago
Read 2 more answers
Can someone please help me with this please!!!!!
Burka [1]

Answer:

a,c,d and e are TRUE.

Step-by-step explanation:

<8 and <5 add upto 180°(supplementary)

<4 and <7 are angles outside and opposite of the transversal(the line that is crossing the parallel lines)

<5 and<7 are 90°(vertical)

<2 and<6 are on the same side of the transversal(corresponding)

4 0
4 years ago
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