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Kay [80]
3 years ago
12

Enter the expression using exponents. 11 × 11 × 11 × 11 × 11 =

Mathematics
1 answer:
Alla [95]3 years ago
6 0

Answer:

the answer should be 11^{5} or 11^5

Explanation:

Since there are five 11 in the equation, the answer should be 11^{5} or 11^5

You shouldn't write 161051 as the answer because it is NOT a exponent.

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The difference between 32.6 and a number is 10.2. Which equation can be used to solve this problem? 32.6 minus y = 10.2 y minus
guapka [62]

Answer:

32.6 - y= 10.2

Step-by-step explanation:

The equation to solve this problem can be written as

32.6 - y= 10.2

Where y is the number that was substracted from 32.6.

If we make y subject of formula we have

y= (32.6-10.2)

y=22.4

Which means the number that was substracted from 32.6 is 22.4 and there difference is 10.2

3 0
3 years ago
Read 2 more answers
5(x+3)-5<br> simplify this.
nignag [31]

Answer:

5x+10

Step-by-step explanation:

Distribute:

=(5)(x)+(5)(3)+−5

=5x+15+−5

Combine Like Terms:

=5x+15+−5

=(5x)+(15+−5)

=5x+10

8 0
3 years ago
There are 12 football teams in a competition. The lions have a probability of 1/12 of winning the competition. How is this true?
MaRussiya [10]
Asuming that all the teams have the same skill levels the game will mostly be chance. The chance of winning will be 1/12 because they are 1 out of 12 teams.
7 0
3 years ago
An experiment consists of drawing 1 card from a standard​ 52-card deck. Let E be the event that the card drawn is a 10. Find​ P(
viva [34]

The are 4 different possibilities to draw a ten, namely a ten of the four different suits. The probability of the event is the ratio of the 4 possibilities and the total number of possible choices, whcih is 52:

P(E) = 4/52 = 1/13 or about 7.7%

6 0
3 years ago
23, 24 And 25 please. Thank you!
Vesna [10]

Step-by-step explanation:

23. area of rect,r = 11 x 3.5 = 38.5cmsq

area of tri, t = 6 x3.5/2 = 10.5 cmsq

area of shaded region, sr = r-t

=> sr = 38.5- 10.5 = 28.5cmsq

24. area of square, s = 10x10 = 100mmsq

area of circle, c = pi x 5^2 = 78.5mmsq

area of shaded region, sr = s - c

=> sr = 100- 78.5 = 22.5mmsq

25. area of circle, c = pi x 6^2 = 113.04insq

area of tri, t = 6x12/2 = 36insq

area of shaded region, sr = c - t

=> sr = 113.04 - 36 = 77.04insq

3 0
3 years ago
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