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3 years ago

1/3x + 5 (x equals -6)

Mathematics

1 answer:

Ket [755]3 years ago

3 0

Answer:

Step-by-step explanation:

1/3x + 5, x = -6

1/3(-6) + 5

-6/3 + 5

-2 + 5

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If 3x+9=5x+1, what is the value of x

Gnesinka [82]

3x+9=5x+1
Subtract 3x from both sides
9=2x+1
Subtract 1 from both sides
8=2x
Divide 2 on both sides
Final Answer: 4=x

3 0

3 years ago

Read 2 more answers

If f(x)=16x-30 and g(x)=14x-6, for which value of x does (f-g)(x)=0

tamaranim1 [39]

Answer:

x=12

Step-by-step explanation:

f(x)=16x-30 and g(x)=14x-6

(f-g)(x)=0

f(x)=16x-30 -(14x-6)

Distribute

= 16x -30 -14x +6

Combine like terms

= 16x-14x -30+6

2x-24

Set this equal to zero

2x-24 =0

Add 24 to each side

2x-24 +24=0+24

2x=24

Divide by 2

2x/2 =24/2

x = 12

5 0

3 years ago

Abe is going to plant 5454 oak trees and 2727 pine trees. Abe would like to plant the trees in rows that all have the same numbe

xxTIMURxx [149]

You would need to find the GCF of 54 and 27.

Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54

Factors of 27: 1, 3, 9, 27

so, the GCF is 27

6 0

3 years ago

Evaluate the definite integrals using properties of the definite integral and the fact that

anygoal [31]

I gather that the given functions satisfy the following definite integral relations:

$\displaystyle \int_{-1}^4 f(x) = -6$

$\displaystyle \int_4^5 f(x) = 10$

$\displaystyle \int_4^5 g(x) =5$

a) By linearity of the integral operator, we have

$\displaystyle \int_{-1}^4 10 f(x) \, dx = 10 \int_{-1}^4 f(x) \, dx = 10 \times (-6) = \boxed{-60}$

b) The integral over an interval is equal to the sum of integrals over a partition of that interval. In this case, the interval [-1, 5] can be written as the interval union [-1, 4] U [4, 5], so that

$\displaystyle \int_{-1}^5 f(x) \, dx = \int_{-1}^4 f(x) \, dx + \int_4^5 f(x) \, dx = -6 + 10 = \boxed{4}$

c) By linearity,

$\displaystyle \int_4^5 (f(x) - g(x)) \, dx = \int_4^5 f(x) \, dx - \int_4^5 g(x) \, dx = 10 - 5 = \boxed{5}$

d) By linearity,

$\displaystyle \int_4^5 (4f(x) + 5g(x)) \, dx = 4 \int_4^5 f(x) \, dx + 5 \int_4^5 g(x) \, dx = 4\times10 + 5\times5 = \boxed{65}$

7 0

2 years ago

Find four consecutive multiples of three that the product of the first and third miners minus eight times the fourth number is n

ZanzabumX [31]

Answer:

The four consecutive multiples of three are 6, 9, 12, and 15

Step-by-step explanation:

let the first multiple of 3 = n

second multiple of 3 = (n + 3)

third multiple of 3 =(n + 6)

fourth multiple of 3 =(n + 9)

product of the first and the third = n(n + 6) = n² + 6n

eight times the fourth number = 8(n + 9) = 8n + 72

The difference between the two = n² + 6n - (8n + 72) = -48

n² + 6n - 8n - 72 = -48

n² - 2n = -48 + 72

n² - 2n = 24

n² - 2n - 24 = 0

n² + 4n - 6n - 24 = 0

n(n + 4) - 6(n + 4) = 0

(n - 6)(n + 4) = 0

n = 6 or - 4

n should be a positive number, thus n = 6

The second multiple of 3 = (n + 3) = 6 + 3 = 9

The third multiple of 3 =(n + 6) = 6 + 6 = 12

The fourth multiple of 3 = (n + 9) = 6 + 9 = 15

7 0

2 years ago