You should do base times hight but firs cut the shape so it would be base times hight because thats the area of a square multiply them then add the 2 sides together
To solve the question we proceed as follows:
length=width=x ; g=height=h
thus
V=x*x*h
v=x^2h
dv/dt=2xh dx/dt+x^2 dh/dt
but
dx/dt=2 ft/sec
dh/dt=-2 ft/sec
thus plugging the values in the equation we get:
dv/dt=2×10×12+10²(-2)
dv/dt=240-200
dv/dt=40 ft³/sec
That is (t^9)^-8
= t^(9*-8)
= t^-72 or 1 / t^72
So I honestly don’t understand this question at all
Indicated here when h(t) = 0, we are to find for the time where the football has reached a certain height.
Then, the values of t would be -0.2 and 2.7.
Since we are to look for the time, it is impossible for us to have an answer that has a negative value. So based from our answer, the solution that we will eliminate is the -0.2 one. Since its value is negative.
So, the correct value would be the 2.7 sec. one.
