All categories

3 years ago

Someone pls answer thx

Mathematics

1 answer:

kotegsom [21]3 years ago

3 0

Answe

~11:

A:x6

b:+3

~12:

A:-3

b:x7

im too lay to helpu on # 13 so figure that out your self ^3^ have a good day

You might be interested in

Does this set of ordered pairs represent a function? Why or why not?

belka [17]

Answer:

Step-by-step explanation:

Recall that for a function to be valid, each input value of x must give us one and only one unique output value for y.

in this case we can see that one of the data sets is (3,-1)

which means that an input of 3 gave an output of -1

but we also see that another data set (3,1)

in this case an input of 3 gave an output of 1.

Because the same x input gives 2 different y outputs, this is not a function.

the answer is A

3 0

3 years ago

Dylan has $14.00 to spend at the book fair. He decides to buy two paperbacks for $4.50 each. Then, he sees some sticker books. A

KonstantinChe [14]

Answer: 5 dollars

Step-by-step explanation:

7 0

3 years ago

heights for 16 year old boys are normally distributed with a mean if 68.3 in and a standard deviation of 2.9 in. find the z-scor

allsm [11]

Simple just decide pie by the universe multiplied bye the square rout of a f1 race car most likely leading too yes

6 0

2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

Solve 12 3/8 divided by 5 1/2 <br><br><br> Please explain :)

ella [17]

Answer:9/4

Step-by-step explanation:

99/8*2/11=9/4*1/1=9/4

You can cancel out 99 and 11 to 9 and 1 as they are multiples of eac hother and you can do the same for 8 and 2 to 4 and 1

7 0

3 years ago

Read 2 more answers