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3 years ago

Which of the following would not be a line in solving the equation:

Mathematics

1 answer:

iVinArrow [24]3 years ago

8 0

Answer:

Step-by-step explanation:

Let's actually solve the equation. By doing so we should readily see which of the given equatins are not part of the solution.

7x - 8 - 5x = 52 becomes 2x - 8 = 52 if we consolidate the x terms. Next, we consolidate the constant terms on the right, obtaining 2x = 60.

Then x = 30 is the solution.

12x = 60 would not be part of the solution.

12x = 44 would not either.

12x - 8 = 52 would not either.

x = 5 would not be part of the solution.

Again: The solution is x = 30.

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Sidana [21]

Number of outcomes when flipping a coin = 2
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So,number of favorable outcomes = 1

Probability of getting a head when flipping a coin = $\frac{1}{2}$

Number of outcomes when rolling a dice = 6
Favorable outcomes are rolling 4,5 or 6.
So,number of favorable outcomes = 3

Probability of getting 4 or a bigger number when rolling a dice = $\frac{3}{6}= \frac{1}{2}$

Thus the probability of getting a head when flipping a coin and getting a number equal to or greater than 4 when a dice is rolled = $\frac{1}{2}* \frac{1}{2} = \frac{1}{4}$

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4 years ago

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Which one doesn’t belong? Why? Explain. please help me

USPshnik [31]

Hi again! I'm assuming that the straight line, which I believe is for y = -2 doesn't belong because everything else has two lines, I mean like it reflects off a certain point on the x or y axis but b) [as I like to call it] doesn't reflect on another axis.

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3 years ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.

Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = $\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})$

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }$

Diagonal 1 (AC) = $\sqrt{(4-0)^2+(-1+1)^2}$ = 4 units

Diagonal 2(BD) = $\sqrt{(2-2)^2+(3+5)^2}$ = 8 units

Now area of the rhombus ABCD = $\frac{1}{2}(\text{AC})(\text{BD})$

= $\frac{1}{2}\times 4\times 8$

= 16 units²

Therefore, area of the given rhombus is 16 units².

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k0ka [10]

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