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2 years ago

11

PLEASE HURRY!!

2 answers:

Kitty [74]2 years ago

5 0

Answer:

I believe it's accumulation.

Explanation:

Gre4nikov [31]2 years ago

3 0

The answer is accumulation because the others don’t make sense

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Is lake Katwe a solution or crater lake and by which process was it formed?

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3 years ago

Read 2 more answers

What is the value of X6? <br><br> Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

2 years ago

Given STU and DEF what is the m

Sonja [21]

Answer:

m<E = 105°

Explanation:

The ratio of the corresponding side lengths of ∆STU and ∆DEF are equal. That is:

$\frac{ST}{DE} = \frac{TU}{EF} = \frac{SU}{DF} = \frac{15}{6} = \frac{10}{4} = \frac{20}{8} = 2.5$ .

According to similarly theorem, if two ∆s are similar, the ratio of their corresponding lengths would be the same. Therefore, ∆STU is similar to ∆DEF.

Since ∆STU ~ ∆DEF, their corresponding angles are congruent. That is:

<S ≅ <D, this means both are 29° each.

<T ≅ <E, this means they are both equal

<U ≅ <F. this means both are 46° each.

Thus:

m<E = 180 - (m<D + m<F) (sum of ∆)

m<E = 180 - (29 + 46) (substitution)

m<E = 180 - 75

m<E = 105°

4 0

2 years ago