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allsm [11]
3 years ago
8

84is30% of what number

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

280

Step-by-step explanation:

30/100 = 84/x

84 x 100 = 8400

8400/30 = 280

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Multiply.<br> 3/4 x -5 1/6
navik [9.2K]

Answer:

-3.87500

Step-by-step explanation:

brainliest!! plez

5 0
3 years ago
A pile of earth removed from an excavation is a cone measuring 6ft high and 30ft across its base. How many trips will it take to
nignag [31]

Answer: 14

Step-by-step explanation:

Given

Excavation cone measures

height h=6\ ft

Diameter d=30\ ft

Truck can dump 125\ ft^3 at a time

The volume of a cone is

V=\dfrac{1}{3}\pi r^2h

Putting values

\Rightarrow V=\dfrac{1}{3}\times \pi\times 15^2\times 6\\\Rightarrow V=1413.9\approx 1414\ ft^3

No of trips(N) required to accumulate this much volume is given by

\Rightarrow N=\dfrac{1414}{125}=13.3\approx 14

Therefore, 14 trips are necessary to accumulate a cone of volume 1414\ ft^3

8 0
3 years ago
The basketball court has an area of 150+175t, with a width of 25. what is the length
Airida [17]
L x w = 150+175t
=> l = (150+175t)/25
l = [25(6+7t)/25]
l = 6+7t
The expression of the length is l=6+7t
3 0
3 years ago
Find the distance between the points (6,5√5) and (4,3√2).<br> 2, 2√2, 2√3
FromTheMoon [43]

Answer:

D=\sqrt{(147-30\sqrt{10}}

Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here we are given two coordinates as

(6,5\sqrt{5} ) , (4,3\sqrt{2} )

Substituting these values in the Distance formula given above we get

D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}

D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\

D=\sqrt{4+125+18-2*15\sqrt{10}}\\D=\sqrt{147-30\sqrt{10}}\\

Hence this is our answer

6 0
3 years ago
Help please will give brainliest
dimulka [17.4K]

Answer:

the black points on the top right marked with the letters are the answers

Hope it Helps

4 0
2 years ago
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