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klasskru [66]
3 years ago
12

The life of light bulbs is distributed normally. the standard deviation of the lifetime is 25 hours and the mean lifetime of a b

ulb is 590 hours. find the probability of a bulb lasting for at most 622 hours. round your answer to four decimal places.
Mathematics
1 answer:
Dominik [7]3 years ago
4 0
The probability is 0.8997.

We will use a z-score to answer this question.  z-scores are given by the formula
z=\frac{X-\mu}{\sigma}

With our information, we have
z=\frac{622-590}{25}=\frac{32}{25}=1.28

Looking this up in a z-table (http://www.z-table.com) we see that the area to the left of this (everything less than, up to this value) is 0.8997.
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Answer:

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Step-by-step explanation:

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We will use volume formula of sphere to solve our given problem.

\text{Volume of sphere}=\frac{4}{3}\pi r^3, where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3

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\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3

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