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lawyer [7]
3 years ago
7

Find the common difference (d) of the arithmetic sequence. It it is not arithmetic, enter "None" in the box. 10, 2, -6, -14, -22

, ... d =?​
Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0
<h3>Answer:  d = -8</h3>

==========================================================

Explanation:

Pick any term that isn't the first term. Then subtract off the previous term. If we get the same result each time, then the sequence is arithmetic, and that result is the common difference.

  • term2 - term1 = 2-10 = -8
  • term3 - term2 = -6-2 = -8
  • term4 - term3 = -14-(-6) = -14+6 = -8
  • term5 - term4 = -22-(-14) = -22+14 = -8

We get -8 each time, so the sequence is arithmetic with common difference d = -8. It says to add -8 to each term to get the next term. This is the same as subtracting 8 from each term to get the next term.

Note how:

  • 10-8 = 2
  • 2-8 = -6
  • -6-8 = -14
  • -14-8 = -22
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Read 2 more answers
what is the first term of a geometric sequence in which the second term is 6 and the fourth term is 54
IRISSAK [1]
For a geometric sequence:
U_{n} = a * r^{n - 1}
U_{n} = the nth term, i.e. U₂ is the second term, U₃ is the third term, etc.
a = first term (U₁)
r = multiplier
n = number corresponding to the postion of the nth term in the sequence, e.g. for U₂, n = 2, for U₃, n = 3

According to the information:
U₂ = 6
U₄ = 54
So:
U_{2} = a * r^{(2) - 1} = 6 \\\\ a * r^{1} = 6 \\\\ ar = 6 \\
U_{4} = a * r^{(4) - 1} = 54 \\\\ a * r^{3} = 54 \\\\ ar^{3} = 54
Now, we have two equations in terms of a and r;
We can work out a by first working out r;
If we let the U₂ eq'n be [1] and the U₄ eq'n be [2];
Then, we do [2] ÷ [1] to cancel out the a and get an equation with only r that we are able to solve and then just solve it, like so:
\frac{ar^{3}}{ar} =  \frac{54}{6} \\\\ r^{2} = 9 \\\\ r = 3
Note: r has to be 3, and not -3, as the two given terms of the sequence tell us that the terms of the sequence will get bigger from each term to the next so r has to be above 1.

Now that we know r, we can sub it back into either [1] or [2] and solve for a, Its quicker and easier to sub it into [1] as we have no powers greater than 1 and we have smaller numbers to deal with (but you would get the same value of a either way), so:
U₂ = ar = 6
a(3) = 6
a = 6/3
a = 2
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