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2 years ago

The table shows the distance Shannon ran over a week.

Mathematics

1 answer:

Sedbober [7]2 years ago

8 0

Answer:

Shannon run 1.5 km more on Friday than on Saturday.

Step-by-step explanation:

From the given table

Distance run on Friday = 4/2 = 2 km

Distance run on Saturday = 1/2 = 0.5 km

In order to run how many more kilometers Shannon run on Friday than on Saturday, we need to subtract the distance run on Saturday from the distance run on Friday.

i.e.

Friday run - Saturday run = 2 - 0.5

= 1.5 km

Thus, Shannon run 1.5 km more on Friday than on Saturday.

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3 years ago

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3 years ago

The perimeter of a rectangular piece of plastic is 30 millimeters. The area is 54 square millimeters. What are the dimensions of

Delvig [45]

Answer:

6 mm and 9 mm are the dimensions of the piece of plastic.

Step-by-step explanation:

Keep in mind the formulas for the area and perimeter of a rectangle:

A = lw

P = 2 (l + w)

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1, 2, 3, 6, 9, 18, 27, 54

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1 mm and 54 mm:

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2 years ago

Plsss help no one answered the other times I put this question

svetlana [45]

Answer:

a) The equation (10s + 8w) represents the calories Bridget ate on Monday and the equation (20s + w) represents the calories she ate the next day.

b) The number of calories in each strawberry is 4 and the number of calories in each vanilla wafer cookie is 19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is s and the number of calories in a vanilla wafer cookie is w , the number of calories Bridget ate on Monday is 10s + 8w. The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s + w.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

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15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

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20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

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3 years ago