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2 years ago

11

+ 2.6.3 Qulz Similar Triangles Question 10 of 10 With similar triangles, the ratios of all three pairs of corresponding sides ar

e equal. O A. True O B. False

1 answer:

AlladinOne [14]2 years ago

4 0

Answer:

A True

Step-by-step explanation:

tell me if I'm worng

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Harlamova29_29 [7]

Answer:

2/8 or 1/4

Step-by-step explanation:

2/8 or 1/4 because the spots on the spinner are blue out of 8 is 2/8 or 1/4

3 0

3 years ago

If θ is an angle in standard position that passes through (-3, 4), find sin2θ.

julia-pushkina [17]

Answer:

Correct answer: sin 2Θ = - 24/25

Step-by-step explanation:

If under the standard position you think that the first arm (side) belongs to the positive direction of the x axis and the second one passes through a given point then it is:

if we form a right triangle with sides 3 and 4 then the hypotenuse is 5.

sin Θ = 4/5 and cos Θ = - 3/5

we know that the formula for double the value of the angle is:

sin 2Θ = 2 sinΘ cosΘ = 2 · 4/5 · ( - 3/5) = - 24/25

sin 2Θ = - 24/25

God is with you!!!

8 0

3 years ago

A population numbers 19,000 organisms initially and grows by 4.8% each year. Suppose P represents population and t represents th

V125BC [204]

Answer:

The exponential model for the population is $P(t) = 19000e^{0.048t}$

Step-by-step explanation:

The exponential model for the population has the following format:

$P(t) = P(0)e^{rt}$

In which P(0) is the initial population and r is the growth rate, as a decimal.

A population numbers 19,000 organisms initially and grows by 4.8% each year.

This means that $P(0) = 19000, r = 0.048$

So

$P(t) = P(0)e^{rt}$

$P(t) = 19000e^{0.048t}$

The exponential model for the population is $P(t) = 19000e^{0.048t}$

8 0

3 years ago

What is the solution set of the equation using the quadratic formula?

oee [108]

(1)

we are given

$x^2+6x+10=0$

we can use quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a , b and c

we get

$a=1,b=6,c=10$

now, we can plug these values into quadratic formula

$x=\frac{-6\pm \sqrt{6^2-4(1)(10)}}{2(1)}$

$x=\frac{-6+\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

we can simplify it

$x=-3+i$

$x=\frac{-6-\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

$x=-3-i$

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

$x^2-8x+14=0$

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so, subtract both sides by 14

$x^2-8x+14-14=0-14$

$x^2-8x=-14$

we can write

$-8x=-2\times 4\times x$

so, we will add both sides by 4^2

$x^2-8x+4^2=-14+4^2$

we get

$x^2-8x+16=-14+16$ ..............Answer

4 0

3 years ago

Which angles intercept a 20 degree arc in a circle? Select all that apply.

kobusy [5.1K]

Answer:

B and D

Step-by-step explanation:

A 20 degree intercepted arc will correspond with two angles: the inscribed angle and the central angle.

The central angle always has the same degree measure as the intercepted arc, so we want a central angle with degree 20. So, that's B.

The inscribed angle is the angle whose vertex is on the circle, not the center. This angle always has half the measure of the intercepted arc, so we want an angle with degree 20/2 = 10. So, that's D.

Thus, the answers are B and D.

Hope this helps!

3 0

3 years ago