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Advocard [28]
3 years ago
9

Please help Ill give brainlest

Mathematics
2 answers:
sveticcg [70]3 years ago
6 0

Answer: D

Step-by-step explanation:

Ksivusya [100]3 years ago
3 0
|2(7)| - (-4) over 3
your answer is 6
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The equation 2x^2+12x=4 is written in the form of 2(x-p)^2+q=0. what is the value of q?
hram777 [196]

1) Factor out the coefficient 2:  2x^2+12x=4 => 2(x^2 + 6x) = 4

2) Complete the square of x^2 + 6x:  x^2 + 6x + 9 - 9.  Then:

                                                    2(x^2 + 6x + 9 - 9) = 4

3) Rewrite the square as the square of a binomial:

                                                    2( [x+3]^2 - 9) = 4, or

                                                     2([x+3]^2)       = 22, or

                                                     2( [x+3]^2 ) - 22 = 0

The value of q is -22.

7 0
3 years ago
Receive 5% commission sold for $ 65000 much is my commission
natka813 [3]

Answer: $3,250

Step-by-step explanation:

5% is the same as 0.05

$65,000 x 0.05 = $3,250

5 0
2 years ago
Need answer ASAP is an assessment!!!!
worty [1.4K]

Answer:

76%, \frac{19}{25}, and Likely

Step-by-step explanation:

The problem tells us that P(red) = 0.76

0.76 as a percentage is represented as 76 out of a 100 or 76%

0.76 as a fraction is \frac{76}{100} which can be simplified to \frac{19}{25} by dividing the numerator and denominator by 4

The probability could be considered "Likely" as it is above 50%

7 0
3 years ago
Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of i
Leokris [45]

Answer:

The mean carrying load of the beams tested is 908.7 pounds per square foot

Step-by-step explanation:

1. Data class 1: 860-879

Midpoint 1: M1=(860+879)/2=1,739/2→M1=869.5

Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

Number of values in data class 3: n3=10

4. Data class 4: 920-939

Midpoint 4: M4=(920+939)/2=1,859/2→M4=929.5

Number of values in data class 4: n4=6

5. Data class 5: 940-959

Midpoint 5: M5=(940+959)/2=1,899/2→M5=949.5

Number of values in data class 5: n5=1


Mean=Sum(Mi*ni)/Sum(ni)

Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

3 0
3 years ago
Solve the following equation. Then place the correct number in the box provided. x/1.2=15
Schach [20]

Answer:

x = 18.

Step-by-step explanation:

x / 1.2 = 15

To isolate x we multiply both sides of ther equation by 1.2:

x = 15 * 1.2

x =  18 (answer).

7 0
3 years ago
Read 2 more answers
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