Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
We let x as the cost of one ounce of Sumatra and y as the cost of one ounce of Celebes Kalossi. For mixture 1, we have 12x + 4y = 32 and for mixture b, we have 4x + 12y = 40
First, Multiply eq. 1 by 4
4(12x + 4y = 32)4 ⇒ 36x + 12y = 96
We now have
(36x + 12y = 96) – (4x + 12y = 40)
<span>X = 1.75 ⇒ cost of one ounce of Sumatra
</span>
Substitute x to either equation to get the value of y
12(1.75) + 4y = 324
y = 32-21
4y = 11
Y = 2.75 ⇒ cost of one ounce of Celebes Kalossi
Yes I believe it does refer to os
A distrobution function is that each key is worth 5 oints how much does it add up to be.
Answer:
coordinates of H = (1, 0)
Coordinates of G = ( - 3.6, -2) or (5.6, -2)
Step-by-step explanation:
E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.
Let the coordinates of H is (x, 0) and G is (a, b).
The length of side EF is
So,
And
Now
Solving (1) and (2)
b = - 2 ,
