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lesantik [10]
3 years ago
10

The Taieri Plain in New Zealand is 6 feet below sea level (or –6 feet). If you are standing 3 feet above sea level, is your elev

ation the opposite of the elevation of the plain
Mathematics
2 answers:
lorasvet [3.4K]3 years ago
4 0

Answer:

mmm points

Step-by-step explanation:

andrew-mc [135]3 years ago
3 0

Answer:

NO

Step-by-step explanation:

Opposite numbers are the same distance from 0 on the number line, but in opposite directions. Steps I would follow:

first, check the directions to make sure they are opposite,

then read the digits, or count the tick marks or compare lengths with dividers or ruler or marks on a piece of paper to see if the distances are the same.

3 is not the opposite of -6

Therefore 6 is the opposite of -6

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Answer:

  • Q11 - 12 sides
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Step-by-step explanation:

<u>Use the formula for sum of interior angles of a regular polygon:</u>

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<u>Each angle A measures:</u>

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  • A = 180(n - 2)n
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  • (180 - A)n = 360
  • n = 360/(180 - A)
<h3>Question 11</h3>

<u>Each angle is 150, then finding n:</u>

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<u>Each angle is 144, find n:</u>

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3 0
3 years ago
Read 2 more answers
In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i
PilotLPTM [1.2K]
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,


was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

\bf \displaystyle \int -32\cdot dt\implies -32t+C&#10;\\\\\\&#10;\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}&#10;\\\\\\&#10;-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}&#10;\\\\\\&#10;\textit{now to get the positional s(t)}&#10;\\\\\\&#10;\displaystyle \int -32t\cdot dt\implies -16t^2+C&#10;\\\\\\&#10;\textit{the initial \underline{position} was 400ft away at 0secs}&#10;\\\\\\&#10;-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}

when will it reach the ground level? let's set s(t) = 0

\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2&#10;\\\\\\&#10;25=t^2\implies \boxed{5=t}


part B)  check the picture below

5 0
3 years ago
Derive the equation of the parabola with a focus at (−5, −5) and a directrix of y = 7
WARRIOR [948]

Answer: The equation of the parabola is (x+5)^2=-24(y-1).

Explanation:

It is given that the focus of the parabola is (-5,-5) and the directrix is y=7.

The standard form of the parabola is,

(x-h)^2=4p(y-k)

Where y=k-p is directrix and (h,k+p) is the focus.

Since focus is given,

(h,k+p)=(-5,-5)

On comparing,

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k+p=-5      .... (1)

The directrix is y=7.

k+p=7       .... (2)

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p=-6

Put p= -6, h= -5 and k=1 in the standard form of the parabola.

(x+5)^2=4(-6)(y-1)

(x+5)^2=-24(y-1)

Therefore, the equation of parabola is (x+5)^2=-24(y-1).

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Dmitrij [34]

Answer:

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Step-by-step explanation:

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