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3 years ago

F(x)= 2/3x -6 what is the value of f(-9)

Mathematics

1 answer:

STALIN [3.7K]3 years ago

3 0

f(-9) means x is -9

Replace x with -9 and solve:

2/3(-9) - 6

Simplify:

-6 - 6 = -12

f(-9) = -12

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PLEASE HELP

katrin [286]

Answer:

3 + 4n -9 + 5n

9n - 6

3 0

3 years ago

X/3 - 38 =42 what is the value of x

madam [21]

X/3 - 38 = 42

x/3 = 80

x = 240

8 0

4 years ago

For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\

kkurt [141]

An inverse function is a function that reverses another function, so we have a function called:

$p(x)$

Then, the inverse function will be as follows:

$p^{-1}(x)$

Given that $y = p(x)$ , we need to isolate x in terms of y:

$y = x^{2} -9$
∴ $y+9 = x^{2}$

So:

$x=+\sqrt{y+9}$ and $x=-\sqrt{y+9}$

therefore, exchanging variables x and y:

$y=+\sqrt{x+9}$ and $y=-\sqrt{x+9}$
$p^{-1}(x)=+\sqrt{x+9}$ and $p^{-1}(x)=-\sqrt{x+9}$

Which are the figures shown below.

7 0

4 years ago

Write a polynomial in factored form that has the given zeros:

wlad13 [49]

Answer:

f(x) = (x + 4)^2*(x - 5)^3

Step-by-step explanation:

For a polynomial P(x) with zeros (or roots):

x₁, x₂, ..., xₙ

And a leading coefficient (the one that multiplies the term of highest degree) A, we can write the polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

Now, some of these roots can be repeated.

For example if x₁ = x₂

Then we say that the root x₁ has a multiplicity of two.

And we write the polynomial as:

P(x) = A*(x - x₁)^2*(x - x₃)*....*(x - xₙ)

Now, if we have a polynomial with the roots (or zeros):

Zero at -4 with a multiplicity of 2 (we have the root x = -4 two times)

Zero at 5 with a multiplicity of 3 (we have the root x = 5 3 times)

(And a leading coefficient A = 1, I assume)

This polynomial will be written as:

f(x) = (x - (-4))*(x - (-4))*(x - 5)*(x - 5)*(x - 5)

f(x) = (x + 4)*(x + 4)*(x - 5)*(x - 5)*(x - 5)

f(x) = (x + 4)^2*(x - 5)^3

The correct option is the third one:

4 0

3 years ago

An anonymous survey of college students was taken to determine behaviors regarding alcohol, cigarettes, and illegal drugs. The r

aleksandrvk [35]

To solve the question, we will be using a Venn Diagram. Let's list down what's given first:

855 drank alcohol

657 smoked cigarettes

192 used illegal drugs

418 both drank alcohol and smoked cigarettes

109 drank alcohol and used illegal drugs

116 smoked cigarettes and used illegal drugs

88 engaged in all three

and 251 engaged in none of these

We will draw a Venn Diagram with 3 circles, one for each vice. Then we will start with the intersection of all three and the area outside of the circles (for those who do not engage in vices).

Because we know how many engaged in all 3 vices, we can deduct that number from those who belong to the intersection of 2 vices since they have already been counted in that too.

418 - 88 = 330 drank and smoked, but not used drugs

109 - 88 = 21 drank and used drugs, but not smoked

116 - 88 = 28 smoked and used drugs but not drank

Then, we subtract the numbers in each circle from the total for each vice.

855 - (330 + 88 + 21) = 416 drank only

657 - (330 + 88 + 28) = 211 smoked only

192 - (88 + 21 + 28) = 55 used drugs only

To find the total number of surveyed students, we just need to add all the numbers in the Venn Diagram.

416 + 330 + 88 + 21 + 211 + 28 + 55 + 251 = 1,400

Therefore, there were 1,400 students who were surveyed.

3 0

1 year ago