Answer:
6x^2 - 23x + 20
Step-by-step explanation:
A = L x W
A = (3x - 4) x (2x - 5)
A = 6x^2 - 15x - 8x + 20
A= 6x^2 - 23x + 20
Answer: :)
Step-by-step explanation: thanks
Answer:
After 4 years, the value of the car would be of $5695.31.
Step-by-step explanation:
The formula for compound interest works perfectly in this case:
![a = p {(1 + \frac{r}{n} )}^{nt}](https://tex.z-dn.net/?f=a%20%3D%20p%20%7B%281%20%2B%20%20%5Cfrac%7Br%7D%7Bn%7D%20%29%7D%5E%7Bnt%7D%20)
As in this case the repetitions per annum are just 1 (yearly), we can ignore the n.
Replacing variables with our values, a yields the depreciated value:
![a = 18000 {(1 - 0.25)}^{4} \\ a = 18000 {(0.75)}^{4} \\ a = 18000(0.31640625) \\ a = 5,695.3125 = 5695.31](https://tex.z-dn.net/?f=a%20%3D%2018000%20%7B%281%20-%200.25%29%7D%5E%7B4%7D%20%20%5C%5C%20a%20%3D%2018000%20%7B%280.75%29%7D%5E%7B4%7D%20%20%5C%5C%20a%20%3D%2018000%280.31640625%29%20%5C%5C%20a%20%3D%205%2C695.3125%20%3D%205695.31)
Answer:
Step-by-step explanation: